What is the perimeter of a rectangle with the of 10cm and width 20cm
1 answer:
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Answer:
12.4967 m
≈ 12.5 m
Step-by-step explanation:
From the solution diagram attached, to find /AB/, we apply sine rule:
AB/Sin 140° =AD/Sin 15°
AB = 10/Sin 15° x Sin 140°
= 24.8372 m
To calculate the height of the pole we will calculate BC first. Using the right angle triangle ∠ABC, we have:
Sin ∅ = BC/AB
Sin 25° = BC/ 24.8372
BC = 24.8372 Sin 25°
= 10.4967 m
The height of the pole = BC + 2.0
= 10.4967 + 2.0
= 12.4967
≈ 12.5 m
