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lesya [120]
3 years ago
15

What is the anser to 19468.8÷52=?

Mathematics
1 answer:
marishachu [46]3 years ago
5 0

19468.8 / 52

It would be equal to 374.4

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<img src="https://tex.z-dn.net/?f=-12t%20%C2%B2%20%2B%2040t" id="TexFormula1" title="-12t &sup2; + 40t" alt="-12t &sup2; + 40t"
d1i1m1o1n [39]

Answer:

1.15

Step-by-step explanation:

tan θ=−4/7, and 270°<θ<360°

θ is in 4th quadrant

sec θ = 8.06 / 7 = 1.15

8 0
3 years ago
9 cos(sin¯¹(x)) = √81 – 81x²
Ira Lisetskai [31]

The equation 9cos(sin¯¹(x)) = √(81 – 81x²) is true since L.H.S = R.H.S

To answer the question, we need to know what an equation is

<h3>What is an equation?</h3>

An equation is a mathematical expression that show the relationship between two variables.

Given 9cos(sin¯¹(x)) = √(81 – 81x²), we need to show L.H.S = R.H.S

So, L.H.S = 9cos(sin¯¹(x))

= 9[√{1 - sin²(sin¯¹(x)}] (Since sin²y + cos²y = 1 ⇒ cosy = √[1 - sin²y])

9[√{1 - sin²(sin¯¹(x)}] = √9² × √{1 - sin²(sin¯¹(x)}]

= √[9² × {1 - sin²(sin¯¹(x)}]

= √[81 × {1 - sin²(sin¯¹(x)}]

= √[81 × {1 - x²}]   (since sin²(sin¯¹(x) = [sin(sin¯¹(x)]² = x²)

= √(81 – 81x²)

= R.H.S

So, the equation 9cos(sin¯¹(x)) = √(81 – 81x²) is true since L.H.S = R.H.S

Learn more about equations here:

brainly.com/question/2888445

#SPJ1

6 0
2 years ago
Hi I was a little confused on dilation can anyone help me (will mark Brainly)
Westkost [7]

Just divide the distance of each to point P by 2.

C would be 1 unit above and 2 units to the right of P.

D would be 1 unit below and 2 units to the right of P.

And so on...

Hope this helps

7 0
3 years ago
Suppose that at Northside High, the number of hours per week that seniors spend on homework is approximately Normally distribute
Aliun [14]

Answer:

The mean of the sampling distribution of means for the 36 students is of 18.6 homework hours per week.

Step-by-step explanation:

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this question:

For the population, the mean is 18.6. So, by the Central Limit Theorem, the mean of the sampling distribution is also 18.6.

3 0
3 years ago
PLEASE HELP ASAP I FORGOT HOW TO DO THIS!
nadya68 [22]

Answer:

its A

Step-by-step explanation:

5 0
3 years ago
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