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lesya [120]
3 years ago
15

What is the anser to 19468.8÷52=?

Mathematics
1 answer:
marishachu [46]3 years ago
5 0

19468.8 / 52

It would be equal to 374.4

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An ant looks up to the top of a tree at an angle of elevation of 40 degrees. If the ant is 30 feet from the base of the tree, wh
Alborosie
For the answer to the question above, this is a right triangle problem using the tangent function. 
<span>Tan(x) = Opposite (O) / Adjacent (A) </span>
<span>x = 40 degrees </span>
<span>A = 30 ft </span>
<span>Solve for O </span>
<span>O= Tan (x) * A </span>
<span>O = Tan (40) * 30 </span>
<span>Use your calculator or whatever method to get the tangent of 40 degrees (which is .84) </span>
<span>O = .84 * 30 </span>
<span>O = 25.2 Ft</span>
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What is 424.12 rounded to the nearest 10th<br> ASAP
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424.1

the nearest 10th refers to the first decimal place therefore there would only need to be 1 decimal place. and you don’t the round the 1 up when dropping the 2 because the 2 is less than five.
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Hi! What is y = x^2 -4x +5 vertex form? Please explain how you got this answer. Thanks! :)
Anarel [89]

{x}^{2}  - 4x + 5 = 0 \\  {x}^{2}  - 4x =  - 5 \\   \\  { (\frac{b}{2} )}^{2}  = ( \frac{ - 4}{2} ) = ( { - 2})^{2}  = 4 \\  {x}^{2}  - 4x + 4 =  - 5 + 4 \\  {(x - 2)}^{2}  =  - 1 \\  {(x - 2)}^{2}  + 1
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Which expression is equivalent to 81 1/3 ?
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The half-life of radium-226 is 1600 years. Suppose we have a 27-mg sample.
slega [8]

A function m(t)= m₀e^(-rt) that models the mass remaining after t years is; m(t) = 27e^(-0.00043t)

The amount of sample that will remain after 4000 years is; 4.8357 mg

The number of years that it will take for only 17 mg of the sample to remain is;  1076 years

<h3>How to solve exponential decay function?</h3>

A) Using the model for radioactive decay;

m(t)= m₀e^(-rt)

where;

m₀ is initial mass

r is rate of growth

t is time

Thus, we are given;

m₀ = 27 mg

r = (In 2)/1600 = -0.00043 which shows a decrease by 0.00043

and so we have;

m(t) = 27e^(-0.00043t)

c) The amount that will remain after 4000 years is;

m(4000) = 27e^(-0.00043 * 4000)

m(4000) = 27 * 0.1791

m(4000) = 4.8357 mg

d) For 17 mg to remain;

17 = 27e^(-0.00043 * t)

17/27 = e^(-0.00043 * t)

In(17/27) = -0.00043 * t

-0.4626/-0.00043 = t

t = 1076 years

Read more about Exponential decay function at; brainly.com/question/27822382

#SPJ1

5 0
1 year ago
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