Hold on I just did this today let me go grab the answers rq
Remember the chain rule.
L(x)=f(g(x))
L'(x)=f'(g(x))g'(x)
take the derivative of f(g(x)). just treat them like they are variables. so you get:
h'=f'(g(x))g'(x)
now plug in your x value and evaluate:
h'(1)=f'(g(1))(g'(1))
substitute in values that you know and evaluate again
h'(1)=f'(3)(-3)
h'(1)=(-5)(-3)=15
Answer:
x=-5
Distribute
Subtract 9 from both sides.
Divide both sides by 3.
Answer:
119
Step-by-step explanation:
62+57 = 119