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3 years ago

Please help!!! I will mark best answer!!! Show some kind of work I don’t want to get it wrong!!!

Mathematics

1 answer:

umka2103 [35]3 years ago

6 0

Answer:

Step-by-step explanation:

Vertex is (1,6)

Axis of symmetry is x=1

Min/Max value is (1,6)

The graph is the parabola opening downward.

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A data set has a median of 12, an upper quartile of 15, a lower quartile of 10, a minimum of 4, and a maximum of 20. Which state

ololo11 [35]

Given:

A data set has a median of 12, an upper quartile of 15, a lower quartile of 10, a minimum of 4, and a maximum of 20.

To find:

The correct statement for the box plot.

Solution:

Lower quartile is 10 and upper quartile is 15, so the box will go from 10 to 15.

Median of the data set is 12, so a line dividing the box will be at 12.

Minimum value is 4 and lower quartile is 10, so the left whisker will go from 4 to 10.

Upper quartile is 15 and maximum value is 20, so the right whisker will go from 15 to 20.

Therefore, the correct option is B.

8 0

3 years ago

Read 2 more answers

Nathan goes to the store and buys 2 shorts and 4 shirts for 70$. He later goes to the same store and buys 3 shorts and 3 shirts

Roman55 [17]

Answer:

Each item of clothing costs $12.50

6 0

3 years ago

In ΔJKL, \overline{JL} JL is extended through point L to point M, m∠JKL = (2x+14)^{\circ}(2x+14) ∘ , m∠LJK = (3x+15)^{\circ}(3x+

Sergio039 [100]

Answer:

The value of x =10°

Step-by-step explanation:

Check attachment for solution.

Triangle theorem: the sum of the opposite interior angle is equal to the exterior angle.

<JKL+<LJK=<KLM

2x+14+3x+15=7x+9

Collect like terms

2x+3x-7x=9-14-15

-2x=-20

Divide both side by -2

x=10°

6 0

3 years ago

The midpoint of AB is at (3,7) and A is at (0,-5). Where is B located?

olga nikolaevna [1]

$\bf \textit{middle point of 2 points }\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
% (a,b)
&({{ \square }}\quad ,&{{ \square }})\quad 
% (c,d)
&({{ \square }}\quad ,&{{ \square }})
\end{array}\qquad
% coordinates of midpoint 
\left(\cfrac{{{ x_2}} + {{ x_1}}}{2}\quad ,\quad \cfrac{{{ y_2}} + {{ y_1}}}{2} \right)\qquad thus
\\
----------------------------\\$ $\bf \begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
% (a,b)
A&({{ 0}}\quad ,&{{ -5}})\quad 
% (c,d)
B&({{ \square }}\quad ,&{{ \square }})
\end{array}\qquad
% coordinates of midpoint 
(3,7)\impliedby midpoint\qquad thus
\\ \quad \\
\left(\cfrac{{{ x_2 }} + {{ 0}}}{2}=3\quad ,\quad \cfrac{{{ y_2 }} + {{( -5)}}}{2}=7 \right)\to 
\begin{cases}
\cfrac{{{ x_2 }} + {{ 0}}}{2}=3
\\ \quad \\
\cfrac{{{ y_2 }} + {{ -5}}}{2}=7
\end{cases}
\\ \quad \\
solve\ for\ x_2\ and\ y_2$

3 0

3 years ago

What is equivalent to 4:3

kap26 [50]

Answer:

the answer is 6:8 or 9:12

Step-by-step explanation:

7 0

3 years ago