2 years ago

Can someone please help me

Mathematics

1 answer:

natulia [17]2 years ago

6 0

The answer is $11c^3$ .

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(WILL GIVE BRAINLIEST)Find the polynomial function with real coefficients that has zeros 1, 1 , 2+ i sqrt 3

neonofarm [45]

Answer:

$x^3-x^2(4+i\sqrt{3} )+x(5+i2\sqrt{3} )-(2+i\sqrt{3} )=0$

Step-by-step explanation:

We have given that this polynomial has the given zeroes of 1, 1, and $2+i\sqrt{3}$ , we can express the polynomial in a factored form where each zero has the form x-a (where a is our zero):

polynomial= $(x-1) (x-1) (2+i\sqrt{3})$

= $(x^2+1-2x) (2+i\sqrt{3})$

= $x^3-x^2(4+i\sqrt{3} )+x(5+i2\sqrt{3} )-(2+i\sqrt{3} )=0$

8 0

4 years ago

9/16, 0.25, 5/48, 0.5 least from greatest

zubka84 [21]

Answer:

9/16, 0.5, 0.25, 5/48

Step-by-step explanation:

hope this helps

4 0

3 years ago

Read 2 more answers

I'm sooooo booorreed F.UUUUUUU.CCCCCC.KKKK!!!!!!!!

Lubov Fominskaja [6]

Answer:

What do you need?

Step-by-step explanation:

I mean there wasn't a question to answer here

7 0

3 years ago

What property could be used to solve x divided by 5=3

SashulF [63]

Answer:

3/5

Step-by-step explanation:

8 0

4 years ago

I need help with this ^

VLD [36.1K]

Answer:

i think 13

Step-by-step explanation:

60+57=117

117/9=13

3 0

3 years ago