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Ivahew [28]
3 years ago
15

Tracy used mental math to find 7×38 as shown below. what is x? 7×38 = 7(40-2) = 7(x)- 7(2)​

Mathematics
1 answer:
qaws [65]3 years ago
4 0

Answer:

x=40

Step-by-step explanation:

subtract first then multiply

7*38=7x-14

move terms 266=7x-14

calculate-7x=-14-266

divide both sides by -7 (-7x=-280)

solution x=40

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The answer is 120 because 4•10=40 and 40•3=120
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26/55 divided by 34/11
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The answer is 13/85. You could find out the answer by doing the reprical multiplication.
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2 years ago
Salomon tracks the weight of his new puppy every 2 weeks. She weighs 10 lbs the
Gekata [30.6K]

Equation (B) "y = 3x + 10" represents the growth of the puppy.

<h3>What are equations?</h3>
  • An equation is a mathematical formula where the "equal to" sign appears between two expressions having the same value.
  • Like 3x plus 5 equals 15, for example.
  • Different types of equations exist, such as linear, quadratic, cubic, and others.
  • The three primary forms of linear equations are the slope-intercept form, standard form, and point-slope form.

So, the equation that represents the situation:

  • The weight increase is: (10, 13, 16, 19, 22, 25)
  • We can observe that every time, there is a rise of 3lbs of weight.
  • Now, let 10 be a constant as the weight is starting from 10 lbs.
  • And 'x' be the number of time Salomon tracks the weight.

Then:

  • y = 3x + 10

For example, Salomon checks the weight for the 6th time then:

  • y = 3x + 10
  • y = 3(5) + 10
  • y = 15 + 10
  • y = 25

So, the equation is correct.

Therefore, equation (B) "y = 3x + 10" represents the growth of the puppy.

Know more about equations here:

brainly.com/question/28937794

#SPJ13

The correct question is given below:
Salomon tracks the weight of his new puppy every 2 weeks. She weighs 10 lbs the day he brings her home. His list for her first 6 "weighs" is as follows: (10, 13, 16, 19, 22, 25}

Which equation represents the growth of the puppy? Select one:

A. y = x + 3

B. y = 3x + 10

C. y = 10x + 3

D. y = x + 10

8 0
9 months ago
Of 580580 samples of seafood purchased from various kinds of food stores in different regions of a country and genetically compa
Lubov Fominskaja [6]

Answer:

a) The 99% confidence interval would be given (0.204;0.296).

b) We have 99% of confidence that the true population proportion of all seafood sold in the country that is mislabeled or misidentified is between (0.204;0.296).  

c) No that's not true. Because the necessary assumptions and conditions for the confidence interval for the proportion are satisifed, so then we can use inferential statistics to interpret the interval to the population of interest.

Step-by-step explanation:

Part a

Data given and notation  

n=580 represent the random sample taken    

X represent the seafood sold in the country that is mislabeled or misidentified by the people

\hat p=0.25 estimated proportion of seafood sold in the country that is mislabeled or misidentified by the people

\alpha=0.01 represent the significance level (no given, but is assumed)    

p= population proportion of seafood sold in the country that is mislabeled or misidentified by the people

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The population proportion have the following distribution

p \sim N(p,\sqrt{\frac{\hat p(1-\hat p)}{n}})

The confidence interval would be given by this formula

\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}

For the 99% confidence interval the value of \alpha=1-0.99=0.01 and \alpha/2=0.005, with that value we can find the quantile required for the interval in the normal standard distribution.

z_{\alpha/2}=2.58

And replacing into the confidence interval formula we got:

0.25 - 2.58 \sqrt{\frac{0.25(1-0.25)}{580}}=0.204

0.25 + 2.58 \sqrt{\frac{0.25(1-0.25)}{580}}=0.296

And the 99% confidence interval would be given (0.204;0.296).

Part b

We have 99% of confidence that the true population proportion of all seafood sold in the country that is mislabeled or misidentified is between (0.204;0.296).  

Part c

A government spokesperson claimed that the sample size was too​ small, relative to the billions of pieces of seafood sold each​ year, to generalize. Is this criticism​ valid?

No that's not true. Because the necessary assumptions and conditions for the confidence interval for the proportion are satisifed, so then we can use inferential statistics to interpret the interval to the population of interest.

4 0
3 years ago
Factor wheels show all the
Zielflug [23.3K]

answer: 2 × 2 × 2 × 2 × 2 = 32

Step-by-step explanation:

32 \\  = 16 \times 2  \\ = 4 \times 4 \times 2  \\ = 2 \times 2 \times 2 \times 2 \times 2

3 0
2 years ago
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