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OLEGan [10]
2 years ago
8

You are seeing multiple errors about device drivers failing to launch at startup. Of the following, which is the best option to

try first? Second?a. Restore the SYSTEM hive from backup.
b. Restore the SAM hive from backup.
c. Perform a startup repair.
d. Perform a Windows 10 reset.
Computers and Technology
1 answer:
HACTEHA [7]2 years ago
8 0
Answer
C. Perform a startup repair.
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Readme [11.4K]
No problem I suppose...
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3 years ago
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What is the following file format called? inv_nbr, inv_name, inv_cost 876521,battery,45.00
kiruha [24]

The  following file format of  inv_nbr, inv_name, inv_cost is called delimited format.

<h3>What is a delimited file in Excel?</h3>

The term "Delimited" is known to be a term that connote a form of  an  TXT file that tends to make use of tabs or an  CSV file that uses commas to  be able to separate and group your data.

Note also that a  delimited file is seen as a form of a given sequential file that is made up of column delimiters.

Therefore, The  following file format of  inv_nbr, inv_name, inv_cost is called delimited format.

Learn more about text format from

brainly.com/question/16397886

#SPJ1

Multiple Choice

fixed-width format

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6 0
2 years ago
PLLZZZZZ HELP I WILL GIVE BRAINLIEST IF ANSWER IS RIGHT
Aloiza [94]

Answer:

The answer is candyCost = int(input("How much is the candy?"))

Explanation:

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3 years ago
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write a java program that prompts the user to enter scores (each number an integer from 0 to 10) and prints the following output
Vladimir [108]

Answer:

Explanation:

The following is written in Java. It continues asking the user for inputs until they enter a -1. Then it saves all the values into an array and calculates the number of values entered, the highest, and lowest, and prints all the variables to the screen. The code was tested and the output can be seen in the attached image below.

import java.util.ArrayList;

import java.util.Arrays;

import java.util.Scanner;

class Brainly {

   public static void main(String[] args) {

       Scanner in = new Scanner(System.in);

       int count = 0;

       int highest, lowest;

       ArrayList<Integer> myArr = new ArrayList<>();

       while (true) {

           System.out.println("Enter a number [0-10] or -1 to exit");

           int num = in.nextInt();

           if (num != -1) {

               if ((num >= 0) && (num <= 10)) {

                   count+= 1;

                   myArr.add(num);

               } else {

                   System.out.println("Wrong Value");

               }

           } else {

               break;

           }

       }

       if (myArr.size() > 3) {

           highest = myArr.get(0);

           lowest = myArr.get(0);

           for (int x: myArr) {

               if (x > highest) {

                   highest = x;

               }

               if (x < lowest) {

                   lowest = x;

               }

           }

           System.out.println("Number of Elements: " + count);

           System.out.println("Highest: " + highest);

           System.out.println("Lowest : " + lowest);

       } else {

           System.out.println("Number of Elements: " + count);

           System.out.println("No Highest or Lowest Elements");

       }

   }

}

4 0
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sasho [114]

Answer:

Sticky notes

Explanation:

I got the question correct

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