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dalvyx [7]
4 years ago
6

The clear emergence of a leader and the development of group norms and cohesiveness are the key indicators of the ________ stage

of group development. A. norming B. performing C. forming D. storming
Computers and Technology
1 answer:
Hatshy [7]4 years ago
4 0

Answer: A)Norming

Explanation: Norming is the behavioral factor shown by the people in which they take effort to the solve a particular issues and difference for the maintenance of harmony and healthy environment. This is a level of the group development where the main aim is creating bond and improving norms in a group.

Other options are incorrect because performing is doing task to achieve goal,forming is producing of well and polite environment is the level where the members push their boundaries and fail in development of group.Thus the correct option is option(A).

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Write a program that can be used to assign seats for a commercial airplane. The airplane has 13 rows, with six seats in each row
d1i1m1o1n [39]

Answer:

See explaination

Explanation:

#include <iostream>

#include <string>

#include <stdio.h>

#include <cst dlib>

using namespace st d;

int main(int argc, char *argv[])

{

int airplane[13][6];

char airchar[13][6];

string ticket;

int row[2];

char seat;

//--------------------------------------------

for(int i = 0; i < 13; i++)

{

for(int j = 0; j < 6; j++)

{

airchar[i][j] = '*';

airplane[i][j] = 0;

}

}

//--------------------------------------------

for(;;)

{

cout<<"Rows 1 and 2 are first class (F C)"<<endl;

cout<<"Rows 3 through 7 are business class (B C)"<<endl;

cout<<"Rows 8 through 13 are economy class (E C)"<<endl;

cout<<endl;

cout<<"* - Available"<<endl;

cout<<"X - Occupied"<<endl;

cout<<endl;

cout<<" \t A\t B\t C\t D\t E\t F"<<endl;

cout<<"Row 1\t"<<airchar[0][0]<<"\t"<<airchar[0][1]<<"\t"

<<airchar[0][2]<<"\t"<<airchar[0][3]<<"\t"<<airchar[0][4]<<"\t"

<<airchar[0][5]<<endl;

cout<<"Row 2\t"<<airchar[1][0]<<"\t"<<airchar[1][1]<<"\t"

<<airchar[1][2]<<"\t"<<airchar[1][3]<<"\t"<<airchar[1][4]<<"\t"

<<airchar[1][5]<<endl;

cout<<"Row 3\t"<<airchar[2][0]<<"\t"<<airchar[2][1]<<"\t"

<<airchar[2][2]<<"\t"<<airchar[2][3]<<"\t"<<airchar[2][4]<<"\t"

<<airchar[2][5]<<endl;

cout<<"Row 4\t"<<airchar[3][0]<<"\t"<<airchar[3][1]<<"\t"

<<airchar[3][2]<<"\t"<<airchar[3][3]<<"\t"<<airchar[3][4]<<"\t"

<<airchar[3][5]<<endl;

cout<<"Row 5\t"<<airchar[4][0]<<"\t"<<airchar[4][1]<<"\t"

<<airchar[4][2]<<"\t"<<airchar[4][3]<<"\t"<<airchar[4][4]<<"\t"

<<airchar[4][5]<<endl;

cout<<"Row 6\t"<<airchar[5][0]<<"\t"<<airchar[5][1]<<"\t"

<<airchar[5][2]<<"\t"<<airchar[5][3]<<"\t"<<airchar[5][4]<<"\t"

<<airchar[5][5]<<endl;

cout<<"Row 7\t"<<airchar[6][0]<<"\t"<<airchar[6][1]<<"\t"

<<airchar[6][2]<<"\t"<<airchar[6][3]<<"\t"<<airchar[6][4]<<"\t"

<<airchar[6][5]<<endl;

cout<<"Row 8\t"<<airchar[7][0]<<"\t"<<airchar[7][1]<<"\t"

<<airchar[7][2]<<"\t"<<airchar[7][3]<<"\t"<<airchar[7][4]<<"\t"

<<airchar[7][5]<<endl;

cout<<"Row 9\t"<<airchar[8][0]<<"\t"<<airchar[8][1]<<"\t"

<<airchar[8][2]<<"\t"<<airchar[8][3]<<"\t"<<airchar[8][4]<<"\t"

<<airchar[8][5]<<endl;

cout<<"Row 10\t"<<airchar[9][0]<<"\t"<<airchar[9][1]<<"\t"

<<airchar[9][2]<<"\t"<<airchar[9][3]<<"\t"<<airchar[9][4]<<"\t"

<<airchar[9][5]<<endl;

cout<<"Row 11\t"<<airchar[10][0]<<"\t"<<airchar[10][1]<<"\t"

<<airchar[10][2]<<"\t"<<airchar[10][3]<<"\t"<<airchar[10][4]<<"\t"

<<airchar[10][5]<<endl;

cout<<"Row 12\t"<<airchar[11][0]<<"\t"<<airchar[11][1]<<"\t"

<<airchar[11][2]<<"\t"<<airchar[11][3]<<"\t"<<airchar[11][4]<<"\t"

<<airchar[11][5]<<endl;

cout<<"Row 13\t"<<airchar[12][0]<<"\t"<<airchar[12][1]<<"\t"

<<airchar[12][2]<<"\t"<<airchar[12][3]<<"\t"<<airchar[12][4]<<"\t"

<<airchar[12][5]<<endl;

cout<<endl;

cout<<"Enter Ticket type (F C, B C, or E C): ";

cin>>ticket;

cout<<"Desired Row: ";

cin>>row[0];

cout<<"Desired seat (A,B,C,D,E or F): ";

cin>>seat;

switch(seat)

{

case 'A':

case 'a':

row[0] = row[0] - 1;

row[1] = 1;

row[1] = row[1] - 1;

break;

case 'B':

case 'b':

row[0] = row[0] - 1;

row[1] = 2;

row[1] = row[1] - 1;

break;

case 'C':

case 'c':

row[0] = row[0] - 1;

row[1] = 3;

row[1] = row[1] - 1;

break;

case 'D':

case 'd':

row[0] = row[0] - 1;

row[1] = 4;

row[1] = row[1] - 1;

break;

case 'E':

case 'e':

row[0] = row[0] - 1;

row[1] = 5;

row[1] = row[1] - 1;

break;

case 'F':

case 'f':

row[0] = row[0] - 1;

row[1] = 6;

row[1] = row[1] - 1;

break;

}

if(ticket == "F C")

{

if(row[0]+1 == 1 || row[0]+1 == 2)

{

if(airplane[row[0]][row[1]] == 0)

{

airplane[row[0]][row[1]] = 1;

airchar[row[0]][row[1]] = 'X';

}

else if(airplane[row[0]][row[1]] == 1)

{

cout<<"Message: Seat "<<row[0] + 1<<seat<<" is already occupied"<<endl;

system("Pause");

}

}

else

{

cout<<"Wrong Class"<<endl;

system("Pause");

system("cls");

continue;

}

}

else if(ticket == "B C")

{

if(row[0]+1 == 3 || row[0]+1 == 4 || row[0]+1 == 5

|| row[0]+1 == 6|| row[0]+1 == 7)

{

if(airplane[row[0]][row[1]] == 0)

{

airplane[row[0]][row[1]] = 1;

airchar[row[0]][row[1]] = 'X';

}

else if(airplane[row[0]][row[1]] == 1)

{

cout<<"Message: Seat "<<row[0] + 1<<seat<<" is already occupied"<<endl;

system("Pause");

}

}

else

{

cout<<"Wrong Class"<<endl;

system("Pause");

system("cls");

continue;

}

}

else if(ticket == "E C")

{

if(row[0]+1 == 8 || row[0]+1 == 9 || row[0]+1 == 10

|| row[0]+1 == 11|| row[0]+1 == 12|| row[0]+1 == 13)

{

if(airplane[row[0]][row[1]] == 0)

{

airplane[row[0]][row[1]] = 1;

airchar[row[0]][row[1]] = 'X';

}

else if(airplane[row[0]][row[1]] == 1)

{

cout<<"Message: Seat "<<row[0] + 1<<seat<<" is already occupied"<<endl;

system("Pause");

}

}

else

{

cout<<"Wrong Class"<<endl;

system("Pause");

system("cls");

continue;

}

}

row[0] = 0;

row[1] = 0;

system("cls");

}

return 0;

}

6 0
4 years ago
Design a 16K x 8 memory using the following ICs:
Montano1993 [528]

Answer:

Required memory size is 16k x 8

16k = 24 x 210 = 214

Hence, No. of address lines = 14

No. of data lines = 8

a) Size of IC 1024 x 1

Total number of ICs required = 16k x 8 / 1024 x 1 = 16 x 8 = 128

b) Size of IC 2k x 4

Total number of ICs required = 16k x 8 / 2k x 4 = 8 x 2 = 16

c) Size of IC 1k x 8

Total number of ICs required = 16k x 8 / 1k x 8 = 16 x 1 = 16

Explanation:

For a, 10 address lines from A0 to A9 are used to select any one of the memory location out of 1024 memory locations present in a IC.

For b, 11 address lines from A0 to A10 are used to select any one of the memory location out of 2k=2048 memory locations present in a IC.

For c, 10 address lines from A0 to A9 are used to select any one of the memory location out of 1k=1024 memory locations present in a IC.

3 0
3 years ago
Write a program that has a conversation with the user. The program must ask for both strings and numbers as input. The program m
konstantin123 [22]

Answer:

yo im sorry eat my cookie

Explanation

doorkoeeworkwoeroewkrwerewrwe

5 0
3 years ago
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