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Neko [114]
1 year ago
6

Ten women sit in 10 seats in a line. All of the 10 get up and then reseat themselves using all 10 seats, each sitting in the sea

t she was in before or a seat next to the one she occupied before. In how many ways can the women be reseated
Mathematics
1 answer:
Alik [6]1 year ago
5 0

Women can be seated in 89 ways.

Let Sn be the number of possible seating arrangements with n women. Consider n≥3 and focus on the rightmost woman. If she goes back to her seat, then there are Sn−1 ways to seat the remaining n−1 women. If he is sitting in the penultimate seat, then the woman who was sitting there before must now sit in the rightmost seat.

This gives us Sn−2 ways to seat another n−2 woman, so we get the recursion Sn=Sn−1+Sn−2. Starting with S1=1 and S2=2 we can calculate S10=89.

For more information about permutation, visit brainly.com/question/11732255

#SPJ4

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Determine which ordered pairs are solutions to the equation 3x+7y=21
mafiozo [28]

Answer:

(0,3) and (7,0) are solutions.

Step-by-step explanation:

In a pair of coordinates, they are always listed as (x,y). Since this is the case, you plug in each coordinate to their respective places.

For (0,3)

3(0) + 7(3) = 21

0 + 21 = 21

For (7,0)

3(7) + 7(0) = 21

21 + 0 = 21

To double check that (1,2) isn't a solution:

3(1) + 7(2) = 21

3 + 14 = 21

17 = 21 X

This doesn't work.

Marking as Brainliest is much appreciated.

7 0
3 years ago
1. 6(4x+1)=78<br>2. 2(x+10)=60<br><br>Solve for x​
postnew [5]

Answer:

1. x= -3

2. x= 20

Step-by-step explanation:

sorry if this is wrong,

7 0
3 years ago
8.5 x 10-2 what is the scientific notation of this?
Butoxors [25]

Answer: 0.085

Step-by-step explanation:

Assuming you mean 10 to the power of -2, shift the decimal point two places to the left.

7 0
3 years ago
A genetic experiment involving peas yielded one sample of offspring consisting of 409 green peas and 171 yellow peas. Use a 0.05
grigory [225]
The usual expectation for this kind of experiment is that the peas would yield green and yellow peas in a 3:1 ratio, or 75% green to 25% yellow. So your null hypothesis is that the proportion of yellow peas is p=0.25.

You're testing the claim that 26% of the offspring will be yellow, which means the alternative hypothesis is that the proportion of yellow peas is actually 0.26, or more generally that the expected proportion is greater than 0.25, or p>0.25.

The test statistic in this case will be

Z=\dfrac{\hat p-p_0}{\sqrt{\dfrac{p_0(1-p_0)}n}}

where p_0 is the proportion assumed under the null hypothesis, \hat p is the measured proportion, and n is the sample size. You have p_0=0.25, \hat p=\dfrac{171}{171+409}\approx0.29, and n=409+171=580, so the test statistic is

Z=\dfrac{0.29-0.25}{\sqrt{\dfrac{0.25\times0.75}{580}}}\approx2.2247

Because you're testing p>p_0, this is a right-tailed test, so the P-value is

\mathbb P(Z>2.2247)\approx0.0131

The critical value for a right-tail test at a 0.05 significance level is Z_\alpha\approx1.6449, which means the rejection region is any test statistic that is larger than this critical value. Since Z>Z_\alpha in this case, we reject the null hypothesis.

So the conclusion for this test is that the sample proportion is indeed statistically significantly different from the proportion suggested by the null hypothesis.
8 0
3 years ago
Read 2 more answers
Can someone please help me I dont get it please i need ASAP
LekaFEV [45]

Answer:

23,040 cm

Step-by-step explanation:

2 × 16 × 6 × 3 × 5 × 2 × 4

6 0
3 years ago
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