Your question is incomplete, here is the complete question;
A football is kicked into the air and follows the path defined by h=-2x^2+16x, where x is the time in seconds and h is the height in meters. What is the maximum height reached by the football?
Answer:
maximum height=h=32 meters
Step-by-step explanation:
The given equation is the equation of the parabola or quadratic equation.
The maximum height of the ball will occur at the axis of symmetry.
For the axis of symmetry let h=0,
so,
comparing this equation to standard quadratic/parabola's equation, we get
a= -2, b=16 and c=0
Formula for axis of symmetry is x=-b/2a
x=-16/2*(-2)
x=-16/-4
x=4 it means axis of symmetry is vertical line through the point x=+4, so the maximum height will occur at x=+4
put x=4 to get maximum height as;
Maximum height
Answer:
3 galllon one is $8 because it is the only thing that you can multiply by 3 to get 24
The 4 gallon one is $9 because it is the only number that you can multiply by 4 to get 36
Step-by-step explanation:
Answer:
I dont get the question, is there suposed to be a chart?
Step-by-step explanation:
You can either find the roots of the quadratic formula using the quadratic formula two find the halfway point or you can use the formula t=-b/2a. Both of the two methods gives you the axis of symmetry (the t value for the vertex).
I will use the second method since I don't like using the quadratic formula.
t=-32/(2x-16)
t=1 second
After you find the t value for the axis of symmetry, you plug it into the formula of the graph to find the height.
h=-16+32+14
h=30 feet
5,740,000( you have to make the number less than 10
5.740000 ( you put a decimal to make it less )
5.74e6 (you count how many times you skipped over to get at the decimal point , and that's your awnser .
