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quester [9]
2 years ago
12

Calling all dazai's ans dazai simps ♡♡♡♡♡♡♡​

Mathematics
1 answer:
Bas_tet [7]2 years ago
6 0
Is this even mathematics?
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Workers in an office of 60 staff were asked their favourite type of take-away.
nikdorinn [45]

Answer:

a = 84°

b = 36°

c = 24°

d = 84°

e = 132°

Step-by-step explanation:

The parameters of the workers in the office are;

The number of staffs in the office = 60 staffs

The take-aways are pizza, curry, fish & chips, kebab and other

The frequency for the above take-aways = 14, 6, 4, 14, and 22 respectively

The variables for the angles representing the above take-aways on the pie chart = 'a', 'b', 'c', 'd', and 'e'; respectively

In order to find the size of the angles that represent each group of workers in the pie chart, we find the ratio of the group size to the total number of workers and we multiply the result by 360° as follows;

∠a = 360° × 14/60 = 84°

∠b = 360° × 6/60 = 36°

∠c = 360° × 4/60 = 24°

∠d = 360° × 14/60 = 84°

∠e = 360° × 22/60 = 132°

5 0
2 years ago
Dexter wrote checks and made the deposits shown in his check registry. What was the change in his balance after these transactio
8090 [49]

Answer:

-51

Step-by-step explanation:

-85

+211

-147

+75

-105

=-51

8 0
2 years ago
Read 2 more answers
Which of the following are true statements about David Hilbert
adoni [48]
Need to know what the options are
8 0
3 years ago
The first five terms of a sequence are
Elena L [17]

Answer:

(a) 7 + 3( n - 1 )

(b) 1006

Step-by-step explanation:

ARITHMETIC SEQUENCE.

The number of term of an Arithmetic progression has the formular :

nth term = a + ( n - 1 ) d

a = 7

d = 10 - 7 = 3

nth term = 7 + ( n - 1 ) 3

= 7 + 3n - 3

= 7 + 3( n - 1 )

Therefore,

the nth term of the sequence

= 7 + 3( n - 1 )

(b) For the 1000th term

= 7 + 3 ( 1000-1 )

= 7 + ( 999 )

7 + 999 = 1006

Therefore,

the 1000th term = 1006

5 0
2 years ago
A certain restaurant offers 8 different salads, 5 different main courses, 6 different desserts. If customers choose one salad, o
Naddika [18.5K]

Answer: E. 1200

Step-by-step explanation:

Given : A certain restaurant offers 8 different salads, 5 different main courses, 6 different desserts.

i.e. No. of choices for different salads= 8  -----(1)

No. of choices for different main courses = 5  ----(2)

No. of choices for different desserts = 6

When we choose two different desserts then we use permutation(repeatition not allowed) :

^6P_2=\dfrac{6!}{(6-2)!}=\dfrac{6\times5\times4!}{4!}=6\times5=30----(3)

[∵ No. of ways to choose r things out of n =^nP_r=\dfrac{n!}{(n-r)!} ]

If customers choose one salad, one main course and two different desserts for their meal , then By Fundamental principle of counting (Multiply (1) , (2) and (3)), the number of  different meals are possible :-

8\times5\times30\\\\=1200

Hence, the correct answer is E. 1200 .

8 0
3 years ago
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