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3 years ago

Who is farthest from the school

Mathematics

1 answer:

postnew [5]3 years ago

7 0

Using the law of cosines:

The grocery store to the school:

Distance = √(7^2 + 10^2 - 2*7*10*cos(100)

Distance = 13.16 miles

The movie store to the school:

Distance = √(7^2 + 10^2 - 2*7*10*cos(120)

Distance = 14.80 miles

The friend is further away.

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The first option.

Step-by-step explanation:

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1 year ago

A) Find a particular solution to y" + 2y = e^3 + x^3. b) Find the general solution.

Reptile [31]

Answer:

a.P.I= $\frac{e^{3x}}{11}+\frac{1}{2}(x^3-3x)$

b.G.S= $C_1Cos \sqrt2 x+C_2 Sin\sqrt2 x+\frac{1}{11}e^{3x}+\frac{1}{2}(x^3-3x}$

Step-by-step explanation:

We are given that a linear differential equation

$y''+2y=e^{3x}+x^3$

We have to find the particular solution

P.I= $\frac{e^{3x}}{D^2+2}+\frac{x^3}{D^2+2}$

P.I= $\frac{e^{3x}}{3^2+2}+\frac{1}{2} x^3(1+\frac{D^2}{2})^{-2}$

P.I= $\frac{e^{3x}}{11}+\frac{1-2\frac{D^2}{4}+3\frac{D^4}{16}+...}{2}x^3$

P.I= $\frac{e^{3x}}{11}+\frac{x^3-2\frac{\cdot3\cdot 2x}{4}}{2}+0}$ (higher order terms can be neglected

P.I= $\frac{e^{3x}}{11}+\frac{1}{2}(x^3-3x)$

b.Characteristics equation

$D^2+2=0$

$D=\pm\sqrt2 i$

C.F= $C_1cos \sqrt2x+C_2 sin\sqrt2 x$

G.S=C.F+P.I

G.S= $C_1Cos \sqrt2 x+C_2 Sin\sqrt2 x+\frac{1}{11}e^{3x}+\frac{1}{2}(x^3-3x)$

3 0

3 years ago

A density curve for all the possible weights between 0 pounds and 10 pounds is in the shape of a rectangle. What is the value of

Evgesh-ka [11]

The total area under the curve must equal 1. Let the value of the density curve be x. Then 10x = 1. Therefore x = 1/10 or 0.1.
The correct answer is D. 0.1.

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3 years ago

Read 2 more answers

Please help me with math!

Lana71 [14]

B should be correct
Hope that helped

4 0

2 years ago