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1 year ago

When drawing the stretchout arc for the pattern of a cone fitting, the radius should be equal to _____.

1 answer:

4 0

When drawing the stretch-out arc for the pattern of a cone fitting, the radius should be equal to the true length of the side.

The 3 tactics typically used in developing patterns are parallel-line, radial-line, and triangular improvement.

To make such objects, a drafter has to first draw them as a pattern or pattern improvement. A pattern improvement additionally known as a stretch out or simply an improvement is a format of an object made on a single flat aircraft.

In radial traces, we develop styles for shapes that have a taper, all element lines (bends) should radiate returned to a not unusual factor, a radius point. We want matters for this procedure to paintings: A radius factor is in the center (right cone). A radius point is inside an inexpensive distance.

Learn more about cone fitting here: brainly.com/question/12753579

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Doss [256]

Answer: I'm sorry I don't know but il try and calculate the answer for you

Step-by-step explanation:

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2 years ago

PLEASE HELP ASAP! NO SCAMS!

pshichka [43]

Answer:

Step-by-step explanation:

Perpendicular means that the slopes of the "old" line and the "new" line are opposite reciprocals; bisector means that the "new" line goes directly through the center of the "old" line. This perpendicular bisector, then, will go directly through the center of the "old" line, cutting it directly in half and leaving in its wake a 90 degree angle. To write this equation, then, of the perpendicular bisector, we need the slope of the old line and the midpoint of the old line. Let's work on the midpoint first:

$M=(\frac{3+6}{2},\frac{5-7}{2})\\M=(\frac{9}{2},\frac{-2}{2})\\M=(\frac{9}{2},-1)$ So the "new" line will go through this point.

Onto the slope:

$m=\frac{-7-5}{6-3}\\m=\frac{-12}{3}$ so the slope is

m = -4. That means that the perpendicular slope is

$m=\frac{1}{4}$ Now we're ready to write the equation:

$y-5=\frac{1}{4}(x-3)$ and

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3 years ago

Read 2 more answers

PLEASE HELP ME!! Find the measure of angle A: Find the measure of angle B:

g100num [7]

Answer:

Measure of angle A is 65 degrees and measure of angle B is 37 degrees.

Step-by-step explanation: First add all of the degrees of excluding x (4+(-9)) which is -5. Then subtract that from 180 since that is the sum of all the angles in a triangle which gives you 185. Then divide it by the number of "x's" that there are which is 5 which gives you 37. So angle B is x which is 37 degrees and angle a is 2(37)-9 which is 65 degrees. Hope this helps.

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2 years ago

If you wanted to make the graph of y=3x+1 steeper, which equation could to use?

Sidana [21]

Answer:

Literally use any answer which has a higher slope so . . .

y = 10x + 1

y = 1000000000000000000x + 1

and so on.

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2 years ago

A triangle ABC has its vertices at A(-2, -3), B(2, 1), and C(5,-1).

maksim [4K]

$~\hfill \stackrel{\textit{\large distance between 2 points}}{d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}}~\hfill ~ \\\\[-0.35em] ~\dotfill\\\\ A(\stackrel{x_1}{-2}~,~\stackrel{y_1}{-3})\qquad B(\stackrel{x_2}{2}~,~\stackrel{y_2}{1}) ~\hfill AB=\sqrt{( 2- (-2))^2 + ( 1- (-3))^2} \\\\\\ AB=\sqrt{(2+2)^2+(1+3)^2}\implies AB=\sqrt{32}\implies \boxed{AB=4\sqrt{2}} \\\\[-0.35em] ~\dotfill$

$B(\stackrel{x_1}{2}~,~\stackrel{y_1}{1})\qquad C(\stackrel{x_2}{5}~,~\stackrel{y_2}{-1}) ~\hfill BC=\sqrt{( 5- 2)^2 + ( -1- 1)^2} \\\\\\ BC=\sqrt{3^2+(-2)^2}\implies BC=\sqrt{9+4}\implies \boxed{BC=\sqrt{13}} \\\\[-0.35em] ~\dotfill\\\\ C(\stackrel{x_1}{5}~,~\stackrel{y_1}{-1})\qquad A(\stackrel{x_2}{-2}~,~\stackrel{y_2}{-3}) ~\hfill CA=\sqrt{( -2- 5)^2 + ( -3- (-1))^2} \\\\\\ CA=\sqrt{(-7)^2+(-3+1)^2}\implies CA=\sqrt{49+(-2)^2}\implies \boxed{CA=\sqrt{53}}$

$\stackrel{\textit{\large perimeter of ABC}}{4\sqrt{2}+\sqrt{13}+\sqrt{53}~~\approx~~ 16.54}$

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2 years ago