Answer:
232°
Step-by-step explanation:
There are a couple of ways to find the desired direction. Perhaps the most straightforward is to add up the coordinates of the travel vectors.
30∠270° +50∠210° = 30(cos(270°), sin(270°)) +50(cos(210°), sin(210°))
= (0, -30) +(-43.301, -25) = (-43.301, -55)
Then the angle from port is ...
arctan(-55/-43.301) ≈ 231.79° . . . . . . . 3rd quadrant angle
The bearing of the ship from port is about 232°.
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<em>Comment on the problem statement</em>
The term "knot" is conventionally used to indicate a measure of speed (nautical mile per hour), not distance. It is derived from the use of a knotted rope to estimate speed. Knots on the rope were typically 47 ft 3 inches apart. As a measure of distance 30 knots is about 1417.5 feet.
Answer:

Step-by-step explanation:



Therefore, the coefficient of
is
.
3 3/8 = 27/8
So (27/8)/(9/1)
(27)(1)/ (8)(9)
The answer is 27/72 or 3/8
Answer:
f(5) = 22
f(9) = 34
Step-by-step explanation:
Plug in 5 and 9 separately for the equation of the x values. Multiply them each and add 7 to get these values 22 and 34.
The ratio of the length to the width is

.
The ratio of the sides will be the same for the scale and actual figures.

I took the L/W of the scale figure
and set it equal to the L/W of the actual figure.
Now we can solve for the unknown width.
Cross-multiplication gives us this,

Divide by 2.4 and simplify,

Hope that helps! :)