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ohaa [14]
3 years ago
8

Person A leaves his home to visit his cousin, person B, who lives 263 miles away. He travels at an average rate 46 miles per hou

r. One half-hour later, person B leaves her house to visit person A, traveling at an average rate of 74 miles per hour. How long after person Bleaves will it be before they meet?
Mathematics
1 answer:
gladu [14]3 years ago
6 0

Answer:

It will take 2 hours after person B leaves before they meet

Step-by-step explanation:

Step 1: Determine expression for calculating speed, distance and time

The expression for calculating distance, speed and time is;

d=s×t

where;

d=distance in miles

s=speed in miles per hour

t=time in hours

Step 2: Distance covered by person A after 0.5 hours

In this case;

d=unknown

s=46 miles per hour

t=0.5 hours

replacing;

d=(46×0.5)=23 miles

Step 3: Determine the remaining distance to person B house

Remainder=Total distance-distance already covered by person A

where;

total distance=263 miles

distance already covered by person A=23 miles

replacing;

Remainder=(263-23)=240 miles

Remaining distance to person B house=240 miles

Step 4: The time it will take for them to meet

The only have a distance (d) of 240 miles left to cover

Since they are moving towards the same direction, there speeds (s) are added together=(46+74)=120 miles per hour

replacing in the expression below;

time=distance/speed

time=(240/120)=2 hours

It will take 2 hours after person B leaves before they meet

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