Solve the following proportion by cross multiplying: ( x - 3 ) / 4 = ( 2x + 2 ) / 6

Mathematics

2 answers:

Inessa05 [86]2 years ago

7 0

<h3>Solution :</h3>

$\implies \: \sf{ \dfrac{x \: - \: 3}{4} \: = \: \dfrac{2x \: + \: 2}{6} } \\ \\ \implies \: \sf{6( x \: - \: 3) \: = \:4(2x \: + \: 2)} \: \\ \\ \implies \: \sf{6 \times ( x \: - \: 3) \: = \: (2x \: + \: 2)}\\ \\ \implies \: \sf{6x \: - \: 18 \: = \:8x \: + \: 8}\\ \\ \implies \sf{6x \: - \: 8x \: = \:18\: + \: 8}\\ \\ \implies \sf{ - 2x \: = \:18\: + \: 8}\\ \\ \implies \sf{ - 2x \: = \: 26}\\ \\ \implies \sf{ - x \: = \: \dfrac{26}{2} }\\ \\ \implies \sf{ - x \: = \: \cancel{\dfrac{26}{2} }}\\ \\ \implies \sf{ - x \: = \: 13}\\ \\ \implies \red{\bf{ x \: = \: - 13}}$

vichka [17]2 years ago

6 0

Answer:

- 13

Step-by-step explanation:

Solving

$\frac{(x - 3)}{4} = \frac{(2x + 2)}{6} \\ \\ cross \: multiplying \\ 6 \times (x - 3) = 4 \times (2x + 2) \\ 6x - 18 = 8x + 8 \\ 6x - 8x = 8 + 18 \\ - 2x = 26 \\ dividing \: bothsides \: by \: - 2 \\ \frac{ - 2x}{ - 2} = \frac{26}{ - 2} \\ x = - 13$

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diamong [38]

The matrix operation is the addition subtraction and multiplication involving matrices. The coordinates of the image can be represented as a matrix obtained from the coordinates of the preimage through matrix operations

The best correct option is option D), (the y-coordinate for the point (8, -7) is to be replaced with a 7 to give (7, -7) as follows:

$\left[\begin{array}{rrrr}1&0\\0&-1\end{array}\right] \left[\begin{array}{rrrr}9&7&3&2\\-3&-7&-7&-5\end{array}\right]$

The reason the above matrix value for the matrix operation are correct are as follows:

Known parameters:

From the diagram, we have that the coordinates of the vertices of the preimage are;

(2, -5), (3, -7), (9, -3), and (7, -7)

The coordinates of the vertices of the image are;

(2, 5), (3, 7), (9, 3), and (7, 7)

Required:

The matrix operation for the transformation of the preimage points to the image points

Solution:

The transformation from the coordinates of the vertices of primage to the vertices of image involves the change in the sign from negative to positive, of the y-values of the image, which can be obtained by multiplying by (-1)

Therefore, the required matrix operation is presented as follows:

$\mathbf{\left[\begin{array}{rrrr}1&0\\0&-1\end{array}\right] \left[\begin{array}{rrrr}9&7&3&2\\-3&-7&-7&-5\end{array}\right]} =\left[\begin{array}{rrrr}9&7&3&2\\3&7&7&5\end{array}\right]$