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Lynna [10]
3 years ago
14

(6 x 10 to the power of -1) - (5 x 10 to the power of -3)

Mathematics
2 answers:
enot [183]3 years ago
7 0

Answer:

\frac{6247}{375000}

Step-by-step explanation:

Hey, Ace here!

We have the equation (6*10)^{-1} - (5*10)^{-3}

Let's simplify by doing the parenthesis first:

60^{-1} - 50^{-3}

According to our exponent rules, a^{-b}=\frac{1^{b}}{a^{b}}

So let's simplify:

\frac{1^{1}}{60^{1}} - \frac{1^{3}}{50^{3}}

Simplify further:

\frac{1}{60} - \frac{1}{125000}

Find a common denominator (which, yes, is a pain):

\frac{1*6250}{60*6250} - \frac{1*3}{125000*3}

Simplify:

\frac{6250}{375000}-\frac{3}{375000}

Now perform the subtraction:

\frac{6247}{375000}

That's your answer. Let me know if you have any questions.

IgorC [24]3 years ago
6 0

Answer:

0.595.

Step-by-step explanation:

.

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2 years ago
The operation manager at a tire manufacturing company believes that the mean mileage of a tire is 30,393 miles, with a standard
Pie

Answer:

52.84% probability that the sample mean would differ from the population mean by less than 339 miles in a sample of 37 tires if the manager is correct

Step-by-step explanation:

To solve this question, we have to understand the normal probability distribution and the central limit theorem:

Normal probability distribution:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a large sample size can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 30393, \sigma = 2876, n = 37, s = \frac{2876}{\sqrt{37}} = 472.81

What is the probability that the sample mean would differ from the population mean by less than 339 miles in a sample of 37 tires if the manager is correct

This probability is the pvalue of Z when X = 30393 + 339 = 30732 subtracted by the pvalue of Z when X = 30393 - 339 = 30054. So

X = 30732

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{30732 - 30393}{472.81}

Z = 0.72

Z = 0.72 has a pvalue of 0.7642.

X = 30054

Z = \frac{X - \mu}{s}

Z = \frac{30054 - 30393}{472.81}

Z = -0.72

Z = -0.72 has a pvalue of 0.2358

0.7642 - 0.2358 = 0.5284

52.84% probability that the sample mean would differ from the population mean by less than 339 miles in a sample of 37 tires if the manager is correct

4 0
3 years ago
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