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Inga [223]
1 year ago
11

What is the value of 3ypower zero​

Mathematics
2 answers:
defon1 year ago
7 0

Answer:

3

Step-by-step explanation:

So anything to the power of zero is equal to 1. So you have the equation: 3y^0=3(1)=3

If this doesn't make much sense, I sometimes like to use identities to show why this is. So since you're most likely learning exponents, you likely know the identity: \frac{x^a}{x^b}=x^{a-b} well you can use this identity to express the equation: \frac{x^a}{x^a}=x^{a-a}=x^0. and since x^a should equal x^a, and it's being divided by it self, this is equal to 1.

Btw if you didn't understand the identity: \frac{x^a}{x^b}=x^{a-b} I'll try to briefly explain it. The reason this is true, is because you can cancel stuff out if it's being multiplied in the denominator and numerator. For example: \frac{3a}{3}. I can cancel out the 3, because if I multiply 3 by a, and then divide by 3, I'm going to be left with a, because they're inverse to each other. This should hold true for exponents. So you can think of the identity more like: \frac{x*x*x...\text{a amount of times}}{x*x*x\text{b amount of times}} seeing it like this might help understand why you subtract, since you're just cancelling out the x's.

I'll give you a more definitive example to help you grasp it in an example so: \frac{2^4}{2^2}=\frac{2*2*2*2}{2*2}=\frac{2*2}{1}=2^2. See how I canceled out 2 of the 2's, well all I was really doing was subtracting 2 from the degree of the numerator, or in other words I was subtracting the degree of the denominator from the numerator since the bases were the same which is exactly what the identity is doing.

postnew [5]1 year ago
4 0

Answer:

3

3 {y}^{0}

= 3 \times 1

= 3

If any numbers or constant power is zero then it will be 1

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anzhelika [568]

Answer:

50

Step-by-step explanation:

40 squared is 1600

30 squared is 900

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6 0
3 years ago
Every ninth person in line at a movie theater gets free popcorn. Every sixth person gets free apple juice. Shani says that the t
pishuonlain [190]

Find the common multiples:

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Multiples of 9: 9, 18, 27, 36, 45

The common multiples are 18 and 36

The first person in line to get both free would be the 18th person and then the 36th person.

So she is correct that the 36th person would get both free, but they wouldn't be the first person to do it.

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3 years ago
70 points!!!! Find the horizontal and the vertical components of f.
choli [55]

Answer:

  • F = (16.74, -2.95)

Explanation:

<u />

<u>1) Horizontal component</u>

The horizontal component is related to the magnitude of the force by the cosine ratio:

  • cos (α) = Fx / | F |

Where α in the angle (-10º), Fx is the horizontal component, and | F | is the magnitude of the force (17).

  • cos(-10º) = Fx / 17 ⇒ Fx = cos (-10º) × 17 = 16.74

<u />

<u>2) Vertical component</u>

The vertical component is related to the magnitude of the force by the sine ratio:

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Where α in the angle (-10º), Fy is the vertical component, and | F | is the magnitude of the force (17).

  • sin(-10º) = Fy / 17 ⇒ Fy = sin (-10º) × 17 = -2.95

<u />

<u>3) Form (x,y)</u>

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6 0
3 years ago
He floor of a moving van is 3 feet off of the ground. The ramp into the van makes a 12° angle with the ground. About how long is
soldier1979 [14.2K]

Given :

Hight of the van from the ground, h = 3 feet.

The ramp into the van makes a 12° angle with the ground.

To Find :

How long is the ramp.

Solution :

Let, length of ramp is l .

So, height of ramp in terms of length is given by :

h = l \times sin\ 12^o\\\\l = \dfrac{h}{sin \ 12^o}\\\\l = \dfrac{3}{sin \ 12^o}\\\\l = 14.429 \ feet

Hence, this is the required solution.

8 0
2 years ago
Name a pair of perpendicular lines: <br>is line BC and AJ perpendicular: explain ​
wel
A pair of perpendicular lines would be line CF and line AJ.

Line BC and line AJ are NOT perpendicular because when a pair of lines are perpendicular, all angles become 90 degrees. It is obvious, in the case, if you were to slide line BC on top of line AJ, the angles will not equal 90 degrees.
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