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Inga [223]
1 year ago
11

What is the value of 3ypower zero​

Mathematics
2 answers:
defon1 year ago
7 0

Answer:

3

Step-by-step explanation:

So anything to the power of zero is equal to 1. So you have the equation: 3y^0=3(1)=3

If this doesn't make much sense, I sometimes like to use identities to show why this is. So since you're most likely learning exponents, you likely know the identity: \frac{x^a}{x^b}=x^{a-b} well you can use this identity to express the equation: \frac{x^a}{x^a}=x^{a-a}=x^0. and since x^a should equal x^a, and it's being divided by it self, this is equal to 1.

Btw if you didn't understand the identity: \frac{x^a}{x^b}=x^{a-b} I'll try to briefly explain it. The reason this is true, is because you can cancel stuff out if it's being multiplied in the denominator and numerator. For example: \frac{3a}{3}. I can cancel out the 3, because if I multiply 3 by a, and then divide by 3, I'm going to be left with a, because they're inverse to each other. This should hold true for exponents. So you can think of the identity more like: \frac{x*x*x...\text{a amount of times}}{x*x*x\text{b amount of times}} seeing it like this might help understand why you subtract, since you're just cancelling out the x's.

I'll give you a more definitive example to help you grasp it in an example so: \frac{2^4}{2^2}=\frac{2*2*2*2}{2*2}=\frac{2*2}{1}=2^2. See how I canceled out 2 of the 2's, well all I was really doing was subtracting 2 from the degree of the numerator, or in other words I was subtracting the degree of the denominator from the numerator since the bases were the same which is exactly what the identity is doing.

postnew [5]1 year ago
4 0

Answer:

3

3 {y}^{0}

= 3 \times 1

= 3

If any numbers or constant power is zero then it will be 1

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Find the scale factor of the dilation. Then tell whether it is enlargement or reduction.​
mariarad [96]

Answer:

  a) 1/2; reduction

  b) 5/4; enlargement

Step-by-step explanation:

In each case, the scale factor is CP'/CP. When it is more than 1, the dilation is an enlargement.

Even before you run the numbers, you can tell if it is an enlargement or not. If the dilated figure is larger, P is closer to C than is P'. If P' is closer to C, then it is a reduction.

a) CP'/CP = (4-2)/4 = 2/4 = 1/2 . . . . a reduction

__

b) CP'/CP = 25/20 = 5/4 . . . . an enlargement

4 0
3 years ago
Which statements are true about the trigonometric ratios of this triangle​
rosijanka [135]

Answer:

Options (1), (2), (3) and (4)

Step-by-step explanation:

By applying the sine and cosine rules in the given triangle,

sinθ = \frac{\text{Opposite side}}{\text{Hypotenuse}}

cosθ = \frac{\text{Adjacent side}}{\text{Hypotenuse}}

cos(30°) = \frac{AC}{AB}

              = \frac{11\sqrt{3} }{22}

              = \frac{\sqrt{3}}{2}

sin(30°) = \frac{BC}{AB}

             = \frac{11}{22}

             = \frac{1}{2}

cos(60°) = \frac{BC}{AB}

              = \frac{11}{22}

              = \frac{1}{2}

sin(60°) = = \frac{AC}{AB}

              = \frac{11\sqrt{3} }{22}

              = \frac{\sqrt{3}}{2}

Options (1), (2), (3) and (4) are the correct options.

3 0
2 years ago
Marcia has $84 less than three times as much as sue. together they have $132. how much money does marcia have?
Brut [27]
Let x = sue
and then let 3x-84 = marcia
therefore
(x)+(3x-84)=132
4x-84=132
4x=216
x=54

however just solving for x doesnt completely solve. it only shows sues money because x = sue
for marcia
3x-84
3(54)-84
162-84
78

therefore Marcia has 78$.
5 0
3 years ago
Consider the following function. f(x) = 7x + 1 x (a) Find the critical numbers of f. (Enter your answers as a comma-separated li
sukhopar [10]

Answer:

a) DNE

b) The function increases for every real value of x.

c) DNE

Step-by-step explanation:

Given a function f(x), the critical points are those in which f^{\prime}(x) = 0, that is, the roots of the first derivative of f(x).

Those critical points let us find the intervals in which the function increases or decreases. If the first derivative in the interval is positive, the function increases in the interval. If it is negative, the function decreases.

If the function increases before a critical point and then, as it passes the critical point, it starts to decrease, we have that the critical point (x_{c}, f(x_{c}) is a relative maximum.If the function decreases before a critical point and then, as it passes the critical point, it starts to increase, we have that the critical point [tex](x_{c}, f(x_{c}) is a relative minimum.If the function has no critical points, it either always increases or always decreases.In this exercise, we have that:[tex]f(x) = 7x + 1

(a) Find the critical numbers of f.

f^{\prime}(x) = 0

f^{/prime}(x) = 7

7 = 0 is false. This means that f has no critical points.

(b) Find the open intervals on which the function is increasing or decreasing.

Since there are no critical points, we know that either the function increases or decreases in the entire real interval.

We have a first order function in the following format:

f(x) = ax + b

In which a > 0.

So the function increases for every real value of x.

(c) Apply the First Derivative Test to identify the relative extremum.

From a), we find that there are no critical numbers. So DNE

7 0
3 years ago
Tamara is making a large omelet and needs 1/ 2 cup of chopped tomatoes. She only has a 1 /8 -cup measuring cup. How many times s
juin [17]

Answer:

4 times

Step-by-step explanation:

1/2 is the same thing as saying 4/8. 1 is half of 2 just as 4 is half of 8 :)

6 0
3 years ago
Read 2 more answers
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