I'm doing a practice, and I'm really confused by this question. Help would really be appreciated!!! **100 PTS!**
2 answers:
Great Question!
The problem we have at hand is known to be a function, which maps elements from one set of objects, ( the domain ) onto another, the range. If we were to consider an ordered pair, say ( x, y ), then the function would map x onto y. The inverse function is simply the reverse. Take the ordered pair (-4,0). Function g would map - 4 onto 0, such that . Therefore, the inverse function would map 0 onto - 4, resulting in
. And there you have it! Our first part is answered!
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This second bit here is interesting. Let -
- Switch x and y,
- And now solve this equation for y,
As you can see, we have taken the inverse of h( x ). As y = h( x ), we can thus conclude the following -
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The composition (h^-1 o h)(-5) is, in other words, h^-1(h(-5)). We can therefore calculate h(-5) and then take it's inverse -
Now we can take it's inverse -
Our solution for this last bit is - 5. And, if you don't feel like reading through this entire explanation just take a look at the " summed up " answer below,
I do hope that helps you!
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<em>What is the value of c in the quadratic </em>?
Before starting to solve, you should notice something - the
quadratic is not in its standard form!
We can easily fix it by adding on both sides:-
We can switch the order of 28 and -11x:-
Now, the quadratic is in its standard form, so we can get down to
finding the value of "c".
Remember, the standard form of a quadratic looks like so:-
Now we can just write our <u>quadratic</u> here:-
Now, can you see what the value of "c" is?
An easy way to <u>remember</u> "c" in quadratics is:-
The "c" in quadratics is the constant.
Henceforth, we conclude that the value of "c" in the given quadratic is:-