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Ganezh [65]
2 years ago
13

Find the values of x work 10% of my grade

Mathematics
2 answers:
Ostrovityanka [42]2 years ago
6 0

Answer:

x = 35

Step-by-step explanation:

1. Add all angles

115+(x+36)+24+(2x+10)+2x

= 5x+185

2. Match 360 and fix

5x+185=360

5x=360-185

5x=175

x=175/5

x=35

Hope this helps

liraira [26]2 years ago
5 0

Answer:

\boxed{\sf x = 35^o}

Step-by-step explanation:

Let's find the value of x :-

\sf 115 + x + 36 + 24 + 2x + 10 + 2x = 360^o

Add the numbers.

  • \sf 185 + x + 2x + 2x = 360

Combine like terms.

  • \sf 5x + 185  = 360

Subtract 185 from both sides.

  • \sf 5x = 175

Divide both sides by 5.

  • \sf x = 35^o

<em><u>--------------------------------------</u></em>

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Matilda recently took a statistics quiz in her math class. in one question, 45 of 900 visitors at a local craft show were survey
KonstantinChe [14]

Answer: See explanation

Step-by-step explanation:

a. what is Matilda's error?

The error by Maltida was that she mistakenly thought the population was the sample size. In this case, the 900 visitors aren't the sample but the population.

The population is referred Tina's the entire pool where the sample is picked by the researcher.

b. what is the actual sample

The actual sample is 45. The sample is the smaller version which can be gotten from the entire population. It is a subset from the population of 900 visitors. Therefore, based on the question, it is 45.

8 0
3 years ago
Riley used the distributive property to find the product of 37 and 24. Which expression
Viktor [21]

Answer:

The expression  Riley could have used to find the product of the two numbers is 24 × (30 + 7).

Step-by-step explanation:

The distribution property for multiplication is:

a\times (b+c)=a\cdot b+a\cdot c

In this case we need to determine the product of 37 and 24.

Compute the product as follows:

37\times 24=24\times (30 +7)

            =(24\times 30)+(24\times 7)\\=720+168\\=888

Thus, the product of 37 and 24 is 888.

5 0
3 years ago
Let A,B, and C be square invertible matrices of the same size. If C has no eigenvalue equal to -1, then (AB + ACB)^-1 is equal t
Kisachek [45]

<em>AB</em> + <em>ACB</em> = <em>A</em> (<em>B</em> + <em>CB</em>) = <em>A</em> (<em>I</em> + <em>C </em>) <em>B</em>

Taking the inverse gives

(<em>A</em> (<em>I</em> + <em>C </em>) <em>B</em>)⁻¹ = <em>B </em>⁻¹ (<em>I</em> + <em>C</em> )⁻¹ <em>A</em> ⁻¹

so the answer is (A)

6 0
3 years ago
Which of the following statements regarding the expansion of (x + y)^n are correct?
kompoz [17]

Answer:

A, B and D are true statements.

Step-by-step explanation:

We are given a binomial expansion

(x+y)^n=^nC_0x^ny^0+^nC_1x^{n-1}y^1+^nC_2x^{n-2}y^2+...........+^nC_nx^0y^n

(x+y)^n=x^n+nx^{n-1}y+^nC_2x^{n-2}y^2+...........nxy^{n-1}+y^n

Now we will check each option

Option A: The coefficients of x^n and y^n both equal 1.

If we see first and last term of the expansion, This statement is true.

Option B: For any term x^ay^b in the expansion, a + b = n.

Let we take 3rd term of expansion ^nC_2x^{n-2}y^2

Here, a=n-2 and b=2

If we do  a+b = n-2+2=n

a+b=n is true statement.

Option C: For any term x^ay^b in the expansion, a - b = n.

Let we take 3rd term of expansion ^nC_2x^{n-2}y^2

Here, a=n-2 and b=2

If we do  a-b = n-2-2=n-4≠n

a-b=n is false statement.

Option D: The coefficients of x^ay^b and x^by^a are equal.

If we take second term from beginning and last of the expansion.

\text{Coefficient From beginning } nx^{n-1}y=n

\text{From last } nxy^{n-1}=n

This statement true.

8 0
3 years ago
Diego was asked to plot these points: (-50, 0), (150, 100), (200, -100), (350, 50), (-250, 0). What interval could he use for ea
ivolga24 [154]

Answer:

Interval of 50 on both axis

Step-by-step explanation:

Given

(x_1,y_1) = (-50,0)

(x_2,y_2) = (150,100)

(x_3,y_3) = (200,-100)

(x_4,y_4) = (350,50)

(x_5,y_5) = (-250,0)

There are several ways to do this, but I will use the observation method, since the dataset is small.

Considering the x-coordinates

x = \{-50,150,200,350,-250}

Each element of the data set is a multiple of 50.

Hence, an interval of 50 can be used on the x-axis

Considering the y-coordinates

y = \{0,100,-100,50,0\}

Each element of the data set is a multiple of 50.

Hence, an interval of 50 can be used on the y-axis

<em>So, an interval of 50 can be used on both axes</em>

5 0
3 years ago
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