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2 years ago

)If 18th February, 2030 falls on Monday then what will be the day on 18th February, 2040

Mathematics

1 answer:

MariettaO [177]2 years ago

6 0

The Saturday will be the day on 18th February 2040 if 18th February 2030 falls on Monday

<h3>What is an arithmetic operation?</h3>

It is defined as the operation in which we do the addition of numbers, subtraction, multiplication, and division. It has a basic four operators that is +, -, ×, and ÷.

We have:

18th February 2030 falls on Monday

To find what will be the day on 18th February 2040

Calculate the expression:

= Given date + Month code + (difference between years) + Numbe of leap year

Leap year = difference between years/4

= (2040-2030)/4

= 10/4 = 2.5 ≈2

= 18 + 3 + (2040-2030) + 2

= 33

Divide 33 by 7 the remainder will be 5

Day code = given day code + remainder

= 1 + 5

= 6 (saturday from the table attahced)

Thus, Saturday will be the day on 18th February 2040 if 18th February 2030 falls on Monday.

Learn more about the arithmetic operation here:

brainly.com/question/20595275

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Step-by-step explanation:

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ANSWER

$( \frac{2}{3} , \frac{1}{5} )$

EXPLANATION

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$\frac{1}{2} x - \frac{3}{4} y = \frac{11}{60} ...(1)$

The second equation is

$\frac{2}{5} x + \frac{1}{6} y = \frac{3}{10} ...(2)$

We want to eliminate y, so we multiply the first equation by

$\frac{4}{5}$

$\frac{4}{5} \times \frac{1}{2} x - \frac{4}{5} \times \frac{3}{4} y = \frac{11}{60} \times \frac{4}{5}$

$\frac{2}{5} x - \frac{3}{5} y = \frac{11}{75} ...(3)$

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$(\frac{2}{3} x - \frac{2}{3} x )+ ( \frac{1}{6} y - - \frac{3}{5}y ) =( \frac{3}{10} - \frac{11}{75} )$

$\frac{1}{6} y + \frac{3}{5}y =\frac{3}{10} - \frac{11}{75}$

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Multiply both sides by

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$\implies \: \frac{30}{23} \times \frac{23}{30}y= \frac{23}{150} \times \frac{30}{23}$

$\implies \: y = \frac{1}{5}$

Substitute into the first equation to solve for x .

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$\frac{1}{2} x - \frac{3}{20} = \frac{11}{60}$

$\frac{1}{2} x = \frac{11}{60} + \frac{3}{20}$

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Multiply both sides by 2.

$2 \times \frac{1}{2} x =2 \times \frac{1}{3}$

$x = \frac{2}{3}$

The solution is

$( \frac{2}{3} , \frac{1}{5} )$

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