If you would like to solve 2x + 5y = -13 and 3x - 4y = -8, you can do this using the following steps:
2x + 5y = -13 /*4
3x - 4y = -8 /*5
_______________
8x + 20y = -52
15x - 20y = -40
_______________
8x + 15x + 20y - 20y = -52 - 40
23x = -92
x = -92 / 23
x = -4
<span>3x - 4y = -8
</span>3 * (-4) - 4y = -8
-12 - 4y = -8
12 + 4y = 8
4y = 8 -12
4y = -4
y = -1
The correct result would be x = -4 and y = -1.
Answer:
Quadrant II
Step-by-step explanation:
(-5,6)
The x coordinate is negative so the quadrant is either 2 or 3
The y coordinate is positive so the quadrant is either 1 or 2
To make both happen, it must be in quadrant 2
Quadrant II
Answer:
Your answer is
Congruent means similar.
Other angle is 69°
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Hi there!
![\large\boxed{\text{33 in}^2}](https://tex.z-dn.net/?f=%5Clarge%5Cboxed%7B%5Ctext%7B33%20in%7D%5E2%7D)
Find the total area by breaking the figure into two rectangles, one trapezoid, and one triangle.
Rectangles:
A = l × w
A = 2.75 × 4 = 11 in²
Solve for the other rectangle's length by subtracting from the total:
12 - 2 - 3 - 4 = 3
A = 3 × 3 = 9 in²
Total rectangle area: 11 + 9 = 20 in²
Trapezoid:
A = 1/2(b1 + b2)h
A = 1/2(4.25 + 2.75)3 = 21/2 = 10.5 in²
Triangle:
A = 1/2(bh)
A = 1/2(2.5 · 2) = 2.5 in²
Add up all of the areas:
20 + 10.5 + 2.5 = 33 in²