3.5 decimals to mixed numbers

How do i find the missing angle measures in triangles

Troyanec [42]

Always remember that the sum of the 3 inside angles is always 180 degrees. That'll get you through the majority of these problems.

4 0

4 years ago

Use the property to complete the statement.

notka56 [123]

Answer:

The answer is b and r=5x+7 is 35x

Step-by-step explanation:

8 0

3 years ago

Hi i know im desperate but pls ill give you BIG BIG points…

Zina [86]

Answer:
mABC = 81°
mCAB = 59°

Let’s start with finding mCAB.
Segment CD is a straight line that runs through A, so we know it is a total of 180°.
The problem tells us that there is a right angle (90°) and gives us that 31° in between. Since they all have to add up to 180, we can do
180 - 90 - 31 = ...59°!

Now that we have mCAB, we can find mABC.
All the angles in any triangle must add up to 180. Since we now know mCAB (59°) and mCBA (40°), we can subtract to find the missing angle.
180 - 59 - 40 = ...81°!

Hope this helps! Brainliest always appreciated

4 0

2 years ago

Read 2 more answers

The Wall Street Journal reported that the age at first startup for 90% of entrepreneurs was 29 years of age or less and the age

Hitman42 [59]

Answer:

(a) $\hat p\sim N(0.90,\ 0.0212^{2}})$

(b) $\hat q\sim N(0.10,\ 0.0212^{2}})$

(c) Not different.

Step-by-step explanation:

The information provided is:

The age at first startup for 90% of entrepreneurs was 29 years of age or less.
The age at first startup for 10% of entrepreneurs was 30 years of age or more.

According to the Central limit theorem, if from an unknown population large samples of sizes n > 30, are selected and the sample proportion for each sample is computed then the sampling distribution of sample proportion follows a Normal distribution.

The mean of this sampling distribution of sample proportion is:

$\mu_{\hat p}=p$

The standard deviation of this sampling distribution of sample proportion is:

$\sigma_{\hat p}=\sqrt{\frac{p(1-p)}{n}}$

(a)

Let p represent the proportion of entrepreneurs whose first startup was at 29 years of age or less.

A sample of n = 200 entrepreneurs is selected.

As n = 200 > 30, according to the Central limit theorem the sampling distribution of sample proportion can be approximated by the normal distribution.

Compute the mean and standard deviation as follows:

$\mu_{\hat p}=p=0.90\\\\\sigma_{\hat p}=\sqrt{\frac{p(1-p)}{n}}=\sqrt{\frac{0.90(1-0.90)}{200}}=0.0212$

So, $\hat p\sim N(0.90,\ 0.0212^{2}})$ .

(b)

Let q represent the proportion of entrepreneurs whose first startup was at 30 years of age or more.

A sample of n = 200 entrepreneurs is selected.

As n = 200 > 30, according to the Central limit theorem the sampling distribution of sample proportion can be approximated by the normal distribution.

Compute the mean and standard deviation as follows:

$\mu_{\hat q}=q=0.10\\\\\sigma_{\hat q}=\sqrt{\frac{q(1-q)}{n}}=\sqrt{\frac{0.10(1-0.10)}{200}}=0.0212$

So, $\hat q\sim N(0.10,\ 0.0212^{2}})$ .

(c)

The standard deviation of sample proportions is also known as the standard error.

The standard deviation of p is, 0.0212.

The standard deviation of q is, 0.0212.

Thus, the standard errors of the sampling distributions in parts (a) and (b) are same.

5 0

3 years ago

I need help!! Bill will spend at most $29 on gifts. So far, he has spent $13. What are the possible additional amounts he will s

mariarad [96]

Answer:

$ is less than or equal to $16

Step-by-step explanation:

5 0

3 years ago