All categories

3 years ago

Please somebody help me and solve this problem

Mathematics

1 answer:

pychu [463]3 years ago

5 0

Answer:

this is the equation for the graph y=(x+3)(x-2)

You might be interested in

Set up a double integral for calculating the flux of the vector field ????⃗ (????⃗ )=????⃗ , where ????⃗ =⟨x,y,z⟩, through the p

Tema [17]

Answer:

-937.5π

Step-by-step explanation:

F (r) = r = (x, y, z) the surface equation z = 3(x^2 + y^2) z_x = 6x, z_y = 6y the normal vector n = (- z_x, - z_y, 1) = (- 6x, - 6y, 1)

Thus, flux ∫∫s F · dS is given as;

∫∫ <x, y, z> · <-z_x, -z_y, 1> dA

=∫∫ <x, y, 3x² + 3y²> · <-6x, -6y, 1>dA , since z = 3x² + 3y²

Thus, flux is;

= ∫∫ -3(x² + y²) dA.

Since the region of integration is bounded by x² + y² = 25, let's convert to polar coordinates as follows:

∫(θ = 0 to 2π) ∫(r = 0 to 5) -3r² (r·dr·dθ)

= 2π ∫(r = 0 to 5) -3r³ dr

= -(6/4)πr^4 {for r = 0 to 5}

= -(6/4)5⁴π - (6/4)0⁴π

= -937.5π

4 0

3 years ago

What is an expression for "Four subtracted from the quotient of X and 3

LUCKY_DIMON [66]

" the quotient " means divide

(x/3) - 4 <== ur expression

4 0

3 years ago

Read 2 more answers

A rectangle has a length of (x + 4) centimeters and a width of 12x centimeters. If the perimeter is 26 centimeters, what is the

STALIN [3.7K]

Answer:

The width of rectangle is $W=\frac{108}{13}\ cm$ or $8\frac{4}{13}\ cm$

Step-by-step explanation:

we know that

The perimeter of rectangle is equal to

$P=2(L+W)$

where

L is the length of rectangle

W is the width of rectangle

we have

$P=26\ cm\\L=(x+4)\ cm\\W=12x\ cm$

substitute

$26=2(x+4+12x)$

solve for x

$26=2(13x+4)$

$26=26x+8$

$26x=26-8$

$26x=18$

$x=\frac{18}{26}$

simplify

$x=\frac{9}{13}$

<em>Find the width of rectangle</em>

$W=12x\ cm$

substitute the value of x

$W=12(\frac{9}{13})=\frac{108}{13}\ cm$

Convert to mixed number

$\frac{108}{13}\ cm=\frac{104}{13}+\frac{4}{13}=8\frac{4}{13}\ cm$

7 0

2 years ago

LuckyWell [14K]

Answer:35 square

Step-by-step explanation:

8 0

3 years ago

What series of transformations to quadrilateral ABCD map the quadrilateral onto quadrilateral EFGH to prove that ABCD≅EFGH ?

Alex17521 [72]

B: a reflection across the x-axis followed by a translation 4 units right.

Comparing the points to their mapped images compares A to E, B to F, C to G, and D to H. In each point, the y-coordinate switches signs and the x-coordinate is subtracted by 4.

Reflections across the x-axis will switch the sign of the y-coordinate, and reflections across the y-axis will switch the sign of the x-coordinate. Since the y-coordinates are the ones whose sign changed, the points must have been reflected across the x-axis.

Translations to the left will cause the x-coordinate to increase, and translations to the right will case the x-coordinate to decrease. Since the x-coordinate of every point was subtracted, this means that the translation must have been to the right.

7 0

3 years ago

Read 2 more answers