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LenKa [72]
2 years ago
15

A product is made up of three parts A B and C .The manufacturing in process is such that the probability of A being defective is

0.2..The probability of B being defective is 0.1 and probability of C being defective is 0.3.Find the probability that the assembled will have
a) No defective
b) at least two defective parts.
Mathematics
1 answer:
Umnica [9.8K]2 years ago
7 0

The probability that there'll be no defective will be 0.504.

<h3>How to calculate the probability?</h3>

Probability of A being defective = 0.2.

Probability of B being defective = 0.1

Probability of C being defective = 0.3.

The probability that there will be no defective will be:

= (1 - 0.2) × (1 - 0.1) × (1 - 0.3)

= 0.8 × 0.9 × 0.7

= 0.504

The probability that there'll be no defect is 0.504.

The probability that there'll be at least two defective part will be:

= (0.2 × 0.1) + (0.2 × 0.3) + (0.1 × 0.3)

= 0.02 + 0.06 + 0.03

= 0.11

The probability that there'll be at least two defects is 0.11.

Learn more about probability on:

brainly.com/question/24756209

#SPJ1

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Mariulka [41]

Answer:

0.225 \Omega =225 m\Omega

Step-by-step explanation:

We know (Ohm second law) that R= \frac{k}{d^2} where k inlcudes the rest of the parameters (material, lenght). In our situation we have k= 0.4\cdot9 \Omega mm^2. The moment the diameter becomes 8mm R becomes

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Answer:

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Step-by-step explanation:

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8 0
3 years ago
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shepuryov [24]

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3 years ago
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5 0
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monitta

Answer:

3\sqrt{3} - 4\sqrt{2}

Step-by-step explanation:

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