Question

A product is made up of three parts A B and C .The manufacturing in process is such that the probability of A being defective is 0.2..The probability of B being defective is 0.1 and probability of C being defective is 0.3.Find the probability that the assembled will have
a) No defective
b) at least two defective parts.

Answer 1

The probability that there'll be no defective will be 0.504.

How to calculate the probability?

Probability of A being defective = 0.2.

Probability of B being defective = 0.1

Probability of C being defective = 0.3.

The probability that there will be no defective will be:

= (1 - 0.2) × (1 - 0.1) × (1 - 0.3)

= 0.8 × 0.9 × 0.7

= 0.504

The probability that there'll be no defect is 0.504.

The probability that there'll be at least two defective part will be:

= (0.2 × 0.1) + (0.2 × 0.3) + (0.1 × 0.3)

= 0.02 + 0.06 + 0.03

= 0.11

The probability that there'll be at least two defects is 0.11.

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