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muminat
3 years ago
8

Please help with these six questions! If you can, please answer them all in one comment. Thank you! :) 1. What is the value of t

he product (6/10)(-4) , in simplified form?
2. For Hanukkah, Flora High school decided to distribute candies at a local elementary school. Each pack contains 35 candies. The school wants to order enough candies for 455 children so that each child gets 5 candies. Which equation can be used to find the number of packs the school needs to order? Answer Choices 1. (455)(7) 2. (455)−(5/35) 3. (455)(175) 4. (455)(5/35)
How many packs does the school need to order?

3. Which value is the product of (-20/48)(6) in simplified form?

4. A barrel contains 1513 liters of water. 34 of the water was used to water plants. How many liters of water was used to water plants? How many liters of water are left in the barrel?

5. −5/25× blank =1 (fill in the blank as to what term equals one)

6. (-5)(-210)=1 Select ALL of the statements that explain why the equation is true. Answer Choices A. The fraction -210 is the same as -15 , which is the additive inverse of -5. B. The fraction -210 is the same as -15 , which is the multiplicative inverse of -5. C. The product of any two rational numbers is always 1. D. The product of two negative rational numbers is always positive. E. The sum of a rational number and its multiplicative inverse is always zero. F. The product of a rational number and its multiplicative inverse is always 1.
Mathematics
2 answers:
Temka [501]3 years ago
6 0
#4
1 barrel = 1513 liter, when we use 34 liter : 1513-34=1479 liter of water was left. 
katrin [286]3 years ago
3 0
#1 is (-12/5).
#3 is (-5/2).
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The perimeter of a rectangle must be less than 156 feet. If the length is known to be 66 feet, find the range of possible widths
balu736 [363]

x = perimeter

x<156

length = 66

so, in order to calculate perimeter you need to add two lengths and two widths

so

156 (perimeter) - 2 (66) = two widths

156 - 132 = 24 (remember this number is two widths added together)

so 24 twice the width SO 12 would be the number that the width can't be larger than

the width has to be less than 12

w < 12

5 0
3 years ago
So when you are adding fractions how do you know when you need to simplify the numbers and how do you simplify?
rosijanka [135]

Let's look at an example.

We'll add the fractions 1/6 and 1/8

Before we can add, the denominators must be the same.

To get the denominators to be the same, we can...

  • multiply top and bottom of 1/6 by 8 to get 8/48
  • multiply top and bottom of 1/8 by 6 to get 6/48

At this point, both fractions involve the denominator 48. We can add the fractions like so

8/48  + 6/48 = (8+6)/48 = 14/48

Add the numerators while keeping the denominator the same the entire time.

The last step is to reduce if possible. In this case, we can reduce. This is because 14 and 48 have the factor 2 in common. Divide each part by 2.

  • 14/2 = 7
  • 48/2 = 24

The fraction 14/48 reduces to 7/24

Overall, 1/6 + 1/8 = 7/24

6 0
2 years ago
If 2tanA=3tanB then prove that,<br>tan(A+B)= 5sin2B/5cos2B-1​
Fed [463]

By definition of tangent,

tan(A + B) = sin(A + B) / cos(A + B)

Using the angle sum identities for sine and cosine,

sin(x + y) = sin(x) cos(y) + cos(x) sin(y)

cos(x + y) = cos(x) cos(y) - sin(x) sin(y)

yields

tan(A + B) = (sin(A) cos(B) + cos(A) sin(B)) / (cos(A) cos(B) - sin(A) sin(B))

Multiplying the right side by 1/(cos(A) cos(B)) uniformly gives

tan(A + B) = (tan(A) + tan(B)) / (1 - tan(A) tan(B))

Since 2 tan(A) = 3 tan(B), it follows that

tan(A + B) = (3/2 tan(B) + tan(B)) / (1 - 3/2 tan²(B))

… = 5 tan(B) / (2 - 3 tan²(B))

Putting everything back in terms of sin and cos gives

tan(A + B) = (5 sin(B)/cos(B)) / (2 - 3 sin²(B)/cos²(B))

Multiplying uniformly by cos²(B) gives

tan(A + B) = 5 sin(B) cos(B) / (2 cos²(B) - 3 sin²(B))

Recall the double angle identities for sin and cos:

sin(2x) = 2 sin(x) cos(x)

cos(2x) = cos²(x) - sin²(x)

and multiplying uniformly by 2, we find that

tan(A + B) = 10 sin(B) cos(B) / (4 cos²(B) - 6 sin²(B))

… = 10 sin(B) cos(B) / (4 (cos²(B) - sin²(B)) - 2 sin²(B))

… = 5 sin(2B) / (4 cos(2B) - 2 sin²(B))

The Pythagorean identity,

cos²(x) + sin²(x) = 1

lets us rewrite the double angle identity for cos as

cos(2x) = 1 - 2 sin²(x)

so it follows that

tan(A + B) = 5 sin(2B) / (4 cos(2B) + 1 - 2 sin²(B) - 1)

… = 5 sin(2B) / (4 cos(2B) + cos(2B) - 1)

… = 5 sin(2B) / (4 cos(2B) - 1)

as required.

5 0
2 years ago
Can someone please help me with this please I really need help
Lubov Fominskaja [6]

Answer:N

Step-by-step explanation:

6 0
2 years ago
Plz help geometry will mark brainliest
stellarik [79]
15+16+10 =41
BH= 41
Bd=15
Df=16
Fh=10

Plz mark me brainalist answer
3 0
2 years ago
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