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muminat
3 years ago
8

Please help with these six questions! If you can, please answer them all in one comment. Thank you! :) 1. What is the value of t

he product (6/10)(-4) , in simplified form?
2. For Hanukkah, Flora High school decided to distribute candies at a local elementary school. Each pack contains 35 candies. The school wants to order enough candies for 455 children so that each child gets 5 candies. Which equation can be used to find the number of packs the school needs to order? Answer Choices 1. (455)(7) 2. (455)−(5/35) 3. (455)(175) 4. (455)(5/35)
How many packs does the school need to order?

3. Which value is the product of (-20/48)(6) in simplified form?

4. A barrel contains 1513 liters of water. 34 of the water was used to water plants. How many liters of water was used to water plants? How many liters of water are left in the barrel?

5. −5/25× blank =1 (fill in the blank as to what term equals one)

6. (-5)(-210)=1 Select ALL of the statements that explain why the equation is true. Answer Choices A. The fraction -210 is the same as -15 , which is the additive inverse of -5. B. The fraction -210 is the same as -15 , which is the multiplicative inverse of -5. C. The product of any two rational numbers is always 1. D. The product of two negative rational numbers is always positive. E. The sum of a rational number and its multiplicative inverse is always zero. F. The product of a rational number and its multiplicative inverse is always 1.
Mathematics
2 answers:
Temka [501]3 years ago
6 0
#4
1 barrel = 1513 liter, when we use 34 liter : 1513-34=1479 liter of water was left. 
katrin [286]3 years ago
3 0
#1 is (-12/5).
#3 is (-5/2).
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Answer:

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Step-by-step explanation:

Given

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To obtain information on the corrosion-resistance properties of a certain type of steel conduit, 45 specimens are buried in soil
Debora [2.8K]

Answer:

statistic value t= 5.43

p-value: < 0.00001.

Step-by-step explanation:

Hello!

To obtain information over the corrosion-resistance properties of a certain type of steel conduit a random sample of 45 specimens was taken and buried for two years.

The study variable is:

X: Max. penetration of a steel conduit.

The data of the sample

n= 45

sample mean X[bar]= 53.4

sample standard deviation S= 4.2

The conduits are manufactured to have a true average penetration of at most 50 mills, symbolically: μ ≤ 50

The hypothesis is:

H₀: μ ≤ 50

H₁: μ > 50

α: 0.05

To choose the corresponding statistic to use to study the population mean, the variable must have a normal distribution. There is no available information to check this, so I'll just assume that the variable has a normal distribution and, since the population variance is unknown and the sample is small, the statistic to use is a Student t.

Under the null hypothesis, the critical region and the p-value are one-tailed.

Critical value:

t_{n-1; 1-\alpha } = t_{44; 0.95} = 1.68

Rejection rule:

Reject the null hypothesis when t ≥ 1.68

t= \frac{53.4 - 50}{\frac{4.2}{\sqrt{45} } }

t= 5.43

The calculated value is greater than the critical value, thedecision is to rject the null hypothesis.

p-value:

P(t ≥ 5.43) = 1 - P(t < 5.43) = < 0.00001.

The p-value is less than α so the decision is to reject the null hypothesis.

Since the null hypothesis was rejected, then the population average of the penetration of the conduits specimens is greater than 50 mils. It is not recommendable to use these conduits.

I hope it helps!

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