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2 years ago

7. Solve the inequality. c – 12 > –1 c < –13 c > 11 c > –13 c > 13

Mathematics

1 answer:

Arte-miy333 [17]2 years ago

4 0

<h3>[Learning] How to solve a one-variable-inequality?</h3>

To solve a one-variable-inequality, isolate the variable on one side of the inequality. This can be done by using the four mathematical operations.

What is the four mathematical operations?

The four mathematical operations include the following:

Addition
Subtraction
Multiplication
Division

These operations can be used to solve equations, inequalities, and more.

<h3>[Solving] Simplifying the inequality:</h3>

Given inequality:

c – 12 > –1

As stated in the previous section, let's isolate the variable (c) using the four mathematical operations. Clearly, we have to add both sides by 12 of the inequality as "c" is being subtracted by 12. Therefore, we get:

⇒ c – 12 + 12 > –1 + 12
⇒ c > –1 + 12

Simplify the right-hand-side to obtain the simplified inequality:

⇒ c > 11

Therefore, option B is the correct/best choice.

Learn more about simplifying inequalities: brainly.com/question/21857626

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4 years ago

According to the manufacturer of a backup UPS device, the normal output voltage is 120 volts. The sample of 40 measured voltage

anyanavicka [17]

Answer:

z = 1.83<1.96

null hypothesis is accepted

The sample is came from a population mean

Step-by-step explanation:

Step :-1

The sample of 40 measured voltage amounts from a unit have a mean of 123.59 volts and a standard deviation of 0.31 volts

given sample size n =40

mean of the sample ×⁻ = 123.59 volts

standard deviation of sample σ = 0.31 volts

Step2:-

Null hypothesis :-

the sample is from a population with a mean equal to 120 volts.

H₀ : μ =120

Alternative hypothesis:-

H₁ : μ ≠120

level of significance:- α =0.05

Step 3:-

The test statistic

$z = \frac{x_{-}-mean }{\frac{S.D}{\sqrt{n} } }$

substitute values and simplification

$z = \frac{123.59-120}{\frac{0.31}{\sqrt{40} } }$

on simplification we get the calculated value

z = 1.83

The tabulated value z =1.96 at 0.05 % level of significance

Conclusion:-

Calculated Z < The tabulated value z =1.96 at 0.05 % level of significance

so the null hypothesis is accepted

The sample is came from a population mean

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3 years ago

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3 years ago

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yawa3891 [41]

2n-35=5

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3 years ago

Read 2 more answers

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ella [17]

Answer:

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Explanation:

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2 years ago