$2.99/20 will be the unit price of soup. Then the amount Riley has to pay for 12 ounce would be 12*2.99/20=$1.794
I don’t understand what you’re trying to find! I think it cut off. If you were talking abt the multiplication it makes 52.3
Answer:
hg
Step-by-step explanation:
Answer:
=9:4
Step-by-step explanation:
The relationship between area and side of triangle is
= (S1/S2)^2= (A1/A2)
=(3/2)^2=(A1/A2)
=9/4=(A1/A2)
=A1:A2=9:4
Answer:
![[12.1175 , 18.4825]](https://tex.z-dn.net/?f=%5B12.1175%20%2C%2018.4825%5D)
Step-by-step explanation:
An (
)% interval confidence for the population average, based on a sample of n individuals is given by:
![[\hat x - T_{\alpha /2} \sqrt{\frac{S^{2}}{n} } , \hat x + T_{\alpha /2} \sqrt{\frac{S^{2}}{n}} ]](https://tex.z-dn.net/?f=%5B%5Chat%20x%20-%20T_%7B%5Calpha%20%2F2%7D%20%5Csqrt%7B%5Cfrac%7BS%5E%7B2%7D%7D%7Bn%7D%20%7D%20%20%2C%20%5Chat%20x%20%2B%20T_%7B%5Calpha%20%2F2%7D%20%5Csqrt%7B%5Cfrac%7BS%5E%7B2%7D%7D%7Bn%7D%7D%20%5D)
, where 
is the sample means, 
is the sample standard deviation, 
is the quantile value of the distribution T with 
degrees of freedom and n is the sample size. thus,
![[\hat x - T_{\alpha /2} \sqrt{\frac{S^{2}}{n} } , \hat x + T_{\alpha /2} \sqrt{\frac{S^{2}}{n}} ] = [15.3 - 2.4334\sqrt{\frac{46.24}{20} } , 15.3 + 2.4334\sqrt{\frac{46.24}{20} } ] =[12.1175 , 18.4825]](https://tex.z-dn.net/?f=%5B%5Chat%20x%20-%20T_%7B%5Calpha%20%2F2%7D%20%5Csqrt%7B%5Cfrac%7BS%5E%7B2%7D%7D%7Bn%7D%20%7D%20%20%2C%20%5Chat%20x%20%2B%20T_%7B%5Calpha%20%2F2%7D%20%5Csqrt%7B%5Cfrac%7BS%5E%7B2%7D%7D%7Bn%7D%7D%20%5D%20%3D%20%5B15.3%20-%202.4334%5Csqrt%7B%5Cfrac%7B46.24%7D%7B20%7D%20%7D%20%2C%2015.3%20%2B%202.4334%5Csqrt%7B%5Cfrac%7B46.24%7D%7B20%7D%20%7D%20%5D%20%3D%5B12.1175%20%2C%2018.4825%5D)
