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alexgriva [62]
3 years ago
10

A table has an area of 12 and a perimeter of 16 ft. What are the dimensions of the table?

Mathematics
2 answers:
Ivenika [448]3 years ago
7 0

l=6

w=2

Area=lw

Area=6×2

area=12

perimeter=2(l+w)

perimeter=2(6+2)

perimeter=2×8

perimeter=16

Mark brianliest if my answer suit your question.

pav-90 [236]3 years ago
3 0

Answer:

2 feet by 6 feet

Step-by-step explanation:

L x b is 12

l x 12/b

perimiter is 16

2 (l plus b) is 16

l plus b is 8

12/b plus b is 8

B² - 8b plus 12 is 0

B2 - 6B- 2b plus 12 is 0

(b- 2) (b-6) is 0

B-2 is 0 and b-6 is 0

B Is 2,6

L = 12/2 is 6

L = 12/6 is 2

so is 2,6

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E(X) = \sum_{i=1}^n X_i P(X_i) = 0*0.031 +1*0.156+ 2*0.313+3*0.313+ 4*0.156+ 5*0.031 = 2.5

We can find the second moment given by:

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And we can calculate the variance with this formula:

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And the deviation is:

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Step-by-step explanation:

For this case we have the following probability distribution given:

X          0            1        2         3        4         5

P(X)   0.031   0.156  0.313  0.313  0.156  0.031

The expected value of a random variable X is the n-th moment about zero of a probability density function f(x) if X is continuous, or the weighted average for a discrete probability distribution, if X is discrete.

The variance of a random variable X represent the spread of the possible values of the variable. The variance of X is written as Var(X).  

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\sum_{i=1}^n P(X_i) = 1

And P(X_i) \geq 0, \forall x_i

So then we have a probability distribution

We can calculate the expected value with the following formula:

E(X) = \sum_{i=1}^n X_i P(X_i) = 0*0.031 +1*0.156+ 2*0.313+3*0.313+ 4*0.156+ 5*0.031 = 2.5

We can find the second moment given by:

E(X^2) = \sum_{i=1}^n X^2_i P(X_i) = 0^2*0.031 +1^2*0.156+ 2^2*0.313+3^2*0.313+ 4^2*0.156+ 5^2*0.031 =7.496

And we can calculate the variance with this formula:

Var(X) =E(X^2) -[E(X)]^2 = 7.496 -(2.5)^2 = 1.246

And the deviation is:

Sd(X) = \sqrt{1.246}= 1.116

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