Answer:
four less than the quotient of a number cubed and seven, increased by three ![(\frac{n^3}{7} -4)+3](https://tex.z-dn.net/?f=%28%5Cfrac%7Bn%5E3%7D%7B7%7D%20-4%29%2B3)
five times the difference of a number squared and six
![5(n^2 -6)](https://tex.z-dn.net/?f=5%28n%5E2%20-6%29)
nine more than the quotient of six and a number cubed, decreased by four
![9+\frac{6}{n^3}-4](https://tex.z-dn.net/?f=9%2B%5Cfrac%7B6%7D%7Bn%5E3%7D-4)
twice the difference of nine and a number squared
![2(9-n^2)](https://tex.z-dn.net/?f=2%289-n%5E2%29)
Step-by-step explanation:
Let n the number of interest we have this:
four less than the quotient of a number cubed and seven, increased by three ![(\frac{n^3}{7} -4)+3](https://tex.z-dn.net/?f=%28%5Cfrac%7Bn%5E3%7D%7B7%7D%20-4%29%2B3)
five times the difference of a number squared and six
![5(n^2 -6)](https://tex.z-dn.net/?f=5%28n%5E2%20-6%29)
nine more than the quotient of six and a number cubed, decreased by four
![9+\frac{6}{n^3}-4](https://tex.z-dn.net/?f=9%2B%5Cfrac%7B6%7D%7Bn%5E3%7D-4)
twice the difference of nine and a number squared:
![2(9-n^2)](https://tex.z-dn.net/?f=2%289-n%5E2%29)
True, the diqualysis is very relevant to the trumopionic.
De only way , you can learn maths is that..
- Avoid the perception that maths is a difficult subject
- Always do more calculations
- Try to solve the Same question that your tutor give to you during your leisure time.
Answer:
i have autism and adhd and add and dmdd so plz dont yell at me that i did not answer it!!!
Step-by-step explanation: