Question

1. TRIATHLON The course for a local

Answer 1

The biking portion of the triathlon is 11.7 miles far

Step-by-step explanation:

Let us revise the relation between the two legs of a right triangle and

the hypotenuse

Hypotenuse = $\sqrt{(leg_{1})^{2}+(leg_{2})^{2}}$

To find the length of the hypotenuse

1. Square the length of each leg

2. Add the squares of the legs

3. Find the square root of the sum

∵ The legs of the triangle consist of a 4 mile  swim and a 11 mile run

∴ $leg_{1}$ = 4

∴ $leg_{2}$ = 11

∵ ( $leg_{1}$ )² = (4)² = 16

∵ ( $leg_{2}$ )² = (11)² = 121

∴ ( $leg_{1}$ )² + ( $leg_{2}$ )² = 16 + 121 = 137

∵ The hypotenuse of  the triangle is the biking portion of the  event

∵ Hypotenuse = $\sqrt{(leg_{1})^{2}+(leg_{2})^{2}}$

∴ Hypotenuse = $\sqrt{137}$ = 11.7

The biking portion of the triathlon is 11.7 miles far

Learn more:

You can learn more about Pythagoras Theorem in brainly.com/question/1238144

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