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kipiarov [429]
2 years ago
14

Find the solutions of each equation on the interval [0,2pi) sin(3pi/2+ x)+sin(3pi/2 +x)= -2

Mathematics
1 answer:
user100 [1]2 years ago
3 0

Answer:

x=0

Step-by-step explanation:

You can combine the equation to get 2sin(3/2 +x) = -2

divide both sides by 2 and you get the equation equal to -1. sin is equal to -1 when the value inside is 3/2 so this is the answer.

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What is the other solution??
Vladimir79 [104]

Answer:

The other solution is 12.

Step-by-step explanation:

Break the solution into groups: (x^2+2x)+(-12x-24)

Factor out the x^2 from the first group to get x(x+2)

Factor out the -12 out of the second group to get -12(x-12)

Here we get (x-12)(x+2)

You can see solutions are -2 and 12.

4 0
3 years ago
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sashaice [31]
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5 0
2 years ago
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Drupady [299]

Answer: A

Step-by-step explanation:

because i did a quiz with the same and i got it right

8 0
3 years ago
What is the inverse of cube root x/3 +1
Ostrovityanka [42]

Answer:

{f}^{ - 1} (x) = 3 {x}^{2}  - 3

Step-by-step explanation:

We want to find the inverse of

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x= \sqrt[3]{ \frac{y}{3} + 1}

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Multiply through by 3

3 {x}^{2}  = y + 3

Subtract 1 from both sides:

y = 3 {x}^{2}  - 3

Therefore the inverse is

{f}^{ - 1} (x) = 3 {x}^{2}  - 3

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Step-by-step explanation:

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