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3 years ago

Write an equation for the line in point-slope form that passes through the given point with the given slope m.

Mathematics

1 answer:

iren2701 [21]3 years ago

5 0

Umm I need help on this question

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2x2x2-1x2+2-2x65= This equation is pretty easy i wanna see yall do it >:) oh and hope yall had a great day :)

cluponka [151]

Answer:

2x2x2-1x2+2-2x65=-122

7 0

3 years ago

What is the equation of a line that passes through the points (3, 6) and (8, 4) in slope intercept form?

MrMuchimi

Answer:

$y=-\frac{2}{5}x +8.4$

Step-by-step explanation:

Gradient

$m =\frac{y-y1}{x-x1}$

$m = \frac{6-4}{3-8}$

$m=-\frac{2}{5}$

Equation of a line

$(y-y1)=m(x-x1)\\$

- Sub one set of points into equation

$(y-6)= -\frac{2}{5} (x-6)$

$y=-\frac{2}{5}x +8.4$

6 0

3 years ago

Highest common factor of 72 and 96

Likurg_2 [28]

Answer:

Step-by-step explanation:

Prime Factorise 72:

$72=2*36\\72=2*2*18\\72=2*2*2*9\\72=2*2*2*3*3\\\\72=2^3*3^2$

Prime factorise 96:

$96=2*48\\96=2*2*24\\96=2*2*2*12\\96=2*2*2*2*6\\96=2*2*2*2*2*3\\96=2^5*3$

Multiply the common factors of $2^3*3^2$ and $2^5*3$ :

$2^3*3=24$

4 0

4 years ago

What is 4/7- 2/7 i rlly need help!

lilavasa [31]

Answer:

2/7

Step-by-step explanation:

4-2=2

4/7 - 2/7 = 2/7

the denominators are the same so just change the numerators

5 0

3 years ago

Read 2 more answers

In parallelogram ABCD, AD = 12 in, m∠C = 46º, m∠DBA = 72º. Find the area of ABCD

dmitriy555 [2]

Answer:

The area of parallelogram ABCD is $78.42 \mathrm{in}^{2}$

Explanation:

Given:

AD = 12 in

$m \angle C=46^{\circ}$

$m \angle D B A=72^{\circ}$

To Find:

The area of parallelogram ABCD=?

Solution:

When we construct the parallelogram with the given data, we get a parallelogram formed by 12 cm as one side and an angle with 46 degrees.

The area of the parallelogram can be calculated by $a b * \sin (a n g l e)$

Substituting the value of a=12 we have

$\text { Area of parallelogram }=12 * \text { bsin } 46$

<u>To find the value of b, </u>

We know that area of a triangle can be expressed as,

$\text { Area of triangle }=(A b / 2) \sin (\text {angle})$

So,

$(12 * B D / 2) * \sin 46=(A B * B D / 2) * \sin 72$

Cancelling BD and 2 on both sides we get,

$12 * \sin 46=A B * \sin 72$

$A B=12 * \frac{\sin 46}{\sin 72}$

Therefore,

$b=\frac{12 \sin 46}{\sin 72}$

Substituting the value of b,

$=12 *\left(\frac{12 \sin 46}{\sin 72}\right) * \sin 46$

=78.42

So the area of the parallelogram is $78.42 \mathrm{in}^{2}$

6 0

4 years ago

Read 2 more answers