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4 years ago

Please help me find the work and awnser to number 2

Mathematics

1 answer:

mrs_skeptik [129]4 years ago

3 0

U need to add something on each side in order to cancel certain numbers out...hope this helped

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Find the measurement?

aliina [53]

Answer:

HG = 28

Step-by-step explanation:

The midsegment MN is half the sum of the 2 parallel bases, that is

$\frac{HG+JF}{2}$ = MN , that is

$\frac{HG+16}{2}$ = 22 ( multiply both sides by 2 )

HG + 16 = 44 ( subtract 16 from both sides )

HG = 28

3 0

3 years ago

Find the height of a square pyramid that has a volume of 8 cubic feet and a base length of 2 feet.

WARRIOR [948]

Step-by-step explanation:

Volume of square pyramid

= (Base length)² * (Height/3).

Therefore we have 8 = 2² * (h/3).

=> 8 = 4 * (h/3), h/3 = 2, h = 6.

Hence the height is 6 feet. (1)

6 0

3 years ago

You are given a problem that involves multiplying a positive number and a negative number. Which of the following are reasonable

crimeas [40]

First question:. A and D. Second question: B and C .

7 0

3 years ago

Read 2 more answers

A computer retail store has 1414 personal computers in stock. A buyer wants to purchase 33 of them. Unknown to either the retail

Lorico [155]

Answer:

a) 364 ways

b) 45.33% probability that exactly one of the computers will be defective.

c) 54.67% probability that at least one of the computers selected is defective.

Step-by-step explanation:

The computers are chosen without replacement, so we use the hypergeometric distribution to solve this question.

Hypergeometric distribution:

The probability of x sucesses is given by the following formula:

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

In which:

x is the number of sucesses.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

In this question:

14 computers, so N = 14.

3 defective, so k = 3.

3 will be purchesed, so n = 3.

A) In how many different ways can the 3 computers be chosen?

3 from a set of 14. So

$C_{14,3} = \frac{14!}{3!(14-3)!} = 364$

364 ways

B) What is the probability that exactly one of thecomputers will be defective?

This is P(X = 1).

$P(X = 1) = h(1,14,3,3) = \frac{C_{3,1}*C_{11,2}}{C_{14,3}} = 0.4533$

45.33% probability that exactly one of the computers will be defective.

C) What is the probability that at least one of the computers selected is defective?

Either none is, or at least one is. The sum of the probabilities of these events is 1. So

$P(X = 0) + P(X \geq 1) = 1$

We want $P(X \geq 1)$ . Then

$P(X \geq 1) = 1 - P(X = 0)$

In which

$P(X = 0) = h(0,14,3,3) = \frac{C_{3,0}*C_{11,3}}{C_{14,3}} = 0.4533$

$P(X \geq 1) = 1 - P(X = 0) = 1 - 0.4533 = 0.5467$

54.67% probability that at least one of the computers selected is defective.

5 0

3 years ago

It takes 18 peaches to make 4 jars of peach preserves. How many peaches will be needed to make 14 jars?

Yuki888 [10]

Set up a proportion of peaches/ number of jars.
18/4=x peaches/14
Cross multiply;
4x=252
x=63
So 63 peaches. Hope this helps.

6 0

3 years ago

Read 2 more answers