Find the measurement?

Mathematics

1 answer:

aliina [53]3 years ago

3 0

Answer:

HG = 28

Step-by-step explanation:

The midsegment MN is half the sum of the 2 parallel bases, that is

$\frac{HG+JF}{2}$ = MN , that is

$\frac{HG+16}{2}$ = 22 ( multiply both sides by 2 )

HG + 16 = 44 ( subtract 16 from both sides )

HG = 28

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Solve this problem on paper using all four steps. A girl scout troop sold cookies. If the girls sold 5 more boxes the second wee

Varvara68 [4.7K]

This is a problem where you should make an equation.
Let's say x is the first week. It would mean
First Week : x
Second Week : x + 5
Third Week : 2(x+5)
You need to add these up to make your equation. Your equation will look something like this :
$x+x+5+2(x+5) = 431$
Now you simplify.
$2x+5+2x+10 = 431$
$4x+15 = 431$
$4x = 416$
$x = 104$
That means they sold 104 Boxes in the First Week.
$104+5=109$
So they sold 109 Boxes the Second Week.
109 x 2 = 218
And they sold 218 Boxes the Third Week.

I hope I was useful!

3 0

3 years ago

Read 2 more answers

"A study of the amount of time it takes a mechanic to rebuild the transmission for a 2005 Chevrolet Cavalier shows that the mean

Arada [10]

Answer:

85.31% probability that their mean rebuild time exceeds 8.1 hours.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem:

The Central Limit Theorem estabilishes that, for a random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sample means with size n of at least 30 can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$