<u><em>Question 9:</em></u>
Simplify what is in the parenthesis
Multiply 20 to 5
Divide 50 to 100
<u><em>*(Answer)*=</em></u>
<u><em>Question 10:</em></u>
÷ 
Simplify what is in the parenthesis
Divide 6 to 18
Add 5 to 3
<u><em>*(Answer)*=</em></u> 8
Hope this helps
User who answered: <u><em>BangtanBoyScouts</em></u>
Answer:
+
*LN(|
|) +C
Step-by-step explanation:
we will have to do a trig sub for this
use x=a*tanθ for sqrt(x^2 +a^2) where a=2
x=2tanθ, dx= 2 sec^2 (θ) dθ
this turns 
into integral(sqrt( [2tanθ]^2 +4) * 2sec^2 (θ) )dθ
the sqrt( [2tanθ]^2 +4) will condense into 2sec^2 (θ) after converting tan^2(θ) into sec^2(θ) -1
then it simplifies into integral(4*sec^3 (θ)) dθ
you will need to do integration by parts to work out the integral of sec^3(θ) but it will turn into (1/2)sec(θ)tan(θ) + (1/2) LN(|sec(θ)+tan(θ)|) +C
then you will need to rework your functions of θ back into functions of x
tanθ will resolve back into 
(see substitutions) while secθ will resolve into 
sec(θ)= is from its ratio identity of hyp/adj where the hyp. is 
and adj is 2 (see tan(θ) ratio)
after resolving back into functions of x, substitute ratios for trig functions:
= + *LN(||) +C
I'm assuming you're subtracting. It would be 3.9. The second one would be 0.65.
Answer:
18.42 m
Step-by-step explanation:
At that point, the ball will be static, with final velocity of 0.
The initial velocity is 19.
The acceleration due to gravity is -9.8 m/s^2.
We now have to use an equation of kinematics shown below:
Where
is the final velocity
is the initial velocity
a is -9.8
s is the distance we are looking for
Lets substitute and find the answer:
Step-by-step explanation:
W/XY=XYZ /XY
W/XY=Z
Z=W/XY
