Question

Tennis player strikes a tennis ball from underneath with her racket. The ball is sent straight up with an initial velocity of 19 m/s. How high above the striking point will the ball travel?

Answer 1

Answer:

18.42 m

Step-by-step explanation:

At that point, the ball will be static, with final velocity of 0.

The initial velocity is 19.

The acceleration due to gravity is -9.8 m/s^2.

We now have to use an equation of kinematics shown below:

$v_f^2=v_0^2+2as$

Where

$v_f$  is the final velocity

$v_0$ is the initial velocity

a is -9.8

s is the distance we are looking for

Lets substitute and find the answer:

$v_f^2=v_0^2+2as\\0=(19)^2+2(-9.8)s\\-361=-19.6s\\s=18.42$