A line in point-slope form has the equation
y = mx + b
where m=slope (increase in y for unit increase in x), and
b=y-intercept (value of y where line cuts y-axis)
The original line is
y=(-1/2)x + 11
so
slope = m = -1/2
Any line perpendicular to a line with slope m has a slope of m1=-1/m
So the slope m1 of the required line
m1 = -1 / (-1/2) = +2
and the required line therefore has an equation of
y=2x+b
Knowing that the line passes through P1=(x1, y1)=(4,-8), we can find b using the point slope form of a line with slope m : (y-y1) = m(x-x1)
where m=+2 as found above.
Substituting values, m=+2, x1=4, y1= -8
y-(-8) = +2(x--4)
simplify
y+8 = 2x-8
=>
y=2x-16 (in point slope form)
See the picture attached to better understand the problem
we know that
90°+∠BAC=180°------> by supplementary angles
∠BAC=90°
125°+∠ABC=180° -----> by supplementary angles
∠ABC=55°
∠BAC+∠ABC+p=180----> <span>sum of the internal angles of a triangle is 180 degrees
</span>p=180-90-55-----> p=35°
the answer isp=35°
Answer:
Step-by-step explanation:
1.60
Answer:
125 students attend.
Step-by-step explanation:
We already know that the drama club made $500 (500 - 400 = 100)
divide 500 by 4 to find out how many students attend the play, and paid $4
500 ÷ 4 = 125
125 students attend.