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Gemiola [76]
2 years ago
12

The liquids having same boiling point cannot be seperated from its mixture by distillation, why?​

Chemistry
2 answers:
kotegsom [21]2 years ago
8 0

Answer:

Because different compounds often have different boiling points, the components often separate from a mixture when the mixture is distilled. The boiling point is the temperature at which the vapor pressure of the liquid phase of a compound equals the external pressure acting on the surface of the liquid.

Explanation:

slavikrds [6]2 years ago
4 0

Answer:

Explanation:

They cannot be separated by distillation since it depends on a liquid's ability to boil at a certain temperature. If you have two liquids with the same boiling temperatures, the proportion of each in the vapor phase will be about equal, making it impossible to separate them. Although they presumably do not have the same freezing point, you might use a different method like chromatography or work with their freezing points instead. You could then selectively crystallize one component while leaving the other as a pure liquid.

____________

Definitions:

Distillation:

#1: The volatilization or evaporation and subsequent condensation of a liquid, as when water is boiled in a retort and then the steam is condensed in a cool receiver.

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1.20×10−8s to nanoseconds
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There are 12 nanoseconds in 1.2\times 10^{-8}\ s.

Explanation:

We need to convert 1.2\times 10^{-8}\ s to nanoseconds.

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1\ s=10^9\ ns

Now using unitary method to solve it such that,

1.2\times 10^{-8}\ s=1.2\times 10^{-8}\ \times 10^9\\\\=1.2\times 10\\\\=12\ ns

So, there are 12 nanoseconds in 1.2\times 10^{-8}\ s.

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6b<br> Which of the following is a starting compound during<br> cellular respiration?
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A mixture of 0.600 mol of bromine and 1.600 mol of iodine is placed into a rigid 1.000-L container at 350°C.
kaheart [24]

The equilibrium constant of the reaction is 282. Option D

<h3>What is equilibrium constant?</h3>

The term equilibrium constant refers to the number that often depict how much the process is able to turn the reactants in to products. In other words, if the reactants are readily turned into products, then it follows that the equilibrium constant will be large and positive.

Concentration of bromine = 0.600 mol /1.000-L = 0.600 M

Concentration of iodine = 1.600 mol/1.000-L =  1.600M

In this case, we must set up the ICE table as shown;

              Br2(g) + I2(g) ↔ 2IBr(g)

I          0.6            1.6           0

C      -x                -x             +2x

E    0.6 - x         1.6 - x       1.190

If 2x = 1.190

x = 1.190/2

x = 0.595

The concentrations at equilibrium are;

[Br2] = 0.6 -  0.595 = 0.005

[I2] =   1.6 - 0.595 = 1.005

Hence;

Kc = [IBr]^2/[Br2] [I2]

Kc = ( 1.190)^2/(0.005) (1.005)

Kc = 282

Learn more about equilibrium constant:brainly.com/question/15118952

#SPJ1

4 0
2 years ago
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