The far left of the chart is the minimum(low) value of the box plot.
Answered by Gauthmath must click thanks and mark brainliest
The axis of symmetry can be found by finding the average of the zeros, a derivation from the conservation of energy :P, or by finding the point when the velocity is equal to zero.
df/dx=-6x+12 so df/dx, velocity, equals zero when:
-6x+12=0
6x=12
x=2 so the axis of symmetry is the vertical line x=2
....
average of zeros...
3x^2-12x+6=0
x^2-4x+2=0
x^2-4x=-2
x^2-4x+4=2
(x-2)^2=2
x-2=±√2
x=2±√2 so the average of the zeros is obviously 2.
....
conservation of energy
vf-vi=at When vf=0, this is the maximum value for f(x)...
-vi=at, vi=b and a(acceleration)=2a(from quadratic) and t=x
-b=2ax
x=-b/(2a) in this case
x=-12/(2(-3))
x=-12/-6
x=2
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Answer:
you are possibly the fence that surrounds the pasture field
Once you start working problems like these, it pays to get an appropriate calculator.
.. (x, y, z) ≈ (248.01, 43.63, 88.34) . . . . rounded to 2 decimal places
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The attempt to convert these to fractions with denominators less than 9999 failed.
