Question

An arrow is shot vertically upward at a rate of 210 feet per second. Use the projectile formula

Answer 1

Answer:

The arrow is at a height of 500 feet at time t = 2.35 seconds.

Step-by-step explanation:

It is given that,

An arrow is shot vertically upward at a rate of 250 ft/s, v₀ = 250 ft/s

The projectile formula is given by :

$h=-16t^{2} +vot$

We need to find the time(s), in seconds, the arrow is at a height of 500 ft.

So,

$-16t^{2} +250t=500$

On solving the above quadratic equation, we get the value of t as, t = 2.35 seconds

So, the arrow is at a height of 500 feet at time t = 2.35 seconds. Hence, this is the required solution.

Answer 2

Answer:

An arrow is shot vertically upward at a rate of 210 feet per second. Use the projectile formula

h = −16t2 + v0t

to determine at what time t (in seconds) the height of the arrow will be 300 feet.

Step-by-step explanation:

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