2 years ago

Practice Problems

1 answer:

7 0

Answer: The absolute values of 7 and -7 are equal because they are both a distance of 7 units from 0 on the number line.

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(5x^2+20x) ÷(x+4) divide, it's really important, I thank you for the people who help me in this :)

Sergio [31]

Answer:

Step-by-step explanation:

Given expression: $\frac{5x^2+20x}{x+4}$

Take the common number 5 outside in the numerator.

$\frac{5x^2+20x}{x+4}=\frac{5(x^2+4x)}{x+4}$

Now, take x common in both the terms in numerator.

$\frac{5(x^2+4x)}{x+4}=\frac{5x(x+4)}{x+4}$

Cancel out the common factor in the both numerator and denominator.

$\frac{5x(x+4)}{x+4}=5x$

Hence, the answer is 5x.

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