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Natali [406]
3 years ago
8

round 63,849 to the nearest ten, to the nearest hundred, to the nearest thousand,and the nearest ten thousand

Mathematics
2 answers:
solong [7]3 years ago
5 0
Ok,so the answer would be 63,850 rounded to the nearest ten,63,800 to the nearest hundred,64,000 to the nearest thousand, and finally 60,000 to the nearest ten thousand.pretty simple.hope it helps
Rom4ik [11]3 years ago
3 0
The nearest tens is 63,850. Nearest hundred is 63,800. Nearest thousand is 64,000. Nearest ten thousand is 60,000
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Time to check your progress.
Mamont248 [21]
Let x be total trip distance
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8 0
2 years ago
Given that x=3sin​​θ-2 and y=3cos​​​θ+4.Show that (x+2)²+ (y-4)²=9​​​​​​
asambeis [7]

Answer:

First, plug-in x and y as 3sin​​θ-2 and 3cos​​​θ+4 into the equation, respectively:

((3\sin (\theta)-2)+2)^2 + ((3\cos (\theta)+4)-4)^2 = 9

Then, +2 and -2 cancel out and +4 and -4 cancel out as well, leaving you with:

(3\sin(\theta))^2+(3\cos(\theta))^2=9

We can factor out 3^2 = 9 from both equations:

9(\sin(\theta)^2+cos(\theta)^2) = 9

We know from a trigonometric identity that \sin(\theta)^2+cos(\theta)^2 = 1, meaning we can reduce the equation to:

9(1) = 9

9=9

And therefore, we have shown that (x+2)^2 + (y-4)^2 = 9, if x=3sin​​θ-2 and y=3cos​​​θ+4.

Hope this helped you.

7 0
3 years ago
Write an expression in simplest form for the perimeter of the exercise mat
Verizon [17]
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6 0
3 years ago
Whats the remainder to 5,323 ÷ 34
Maslowich
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5 0
3 years ago
Read 2 more answers
Someone help me... please show work​
frutty [35]

Answer:

x=5

Step-by-step explanation:

Set the 2 equations equal to each other and solve for x.

11x-28=7x-8

add 28 to both sides (-8+28=20)

11x=7x+20

subtract 7x from both sides (11x-7x=4x)

4x=20

divide both sides by 4 to isolate x (20/4=5)

x=5

7 0
4 years ago
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