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3 years ago

Two mechanics worked on a car. the first mechanic worked 10 hours the second mechanic worked for 15 hours together

Mathematics

1 answer:

Allisa [31]3 years ago

6 0

The rate charged by first mechanic is $45 per hour and the rate charged by second mechanic is $50 per hour.

Given mechanic first worked 20 hours and mechanic second worked 15 hours and they charged $1650. The sum of rates of first mechanic and second mechanic is $95 per hour.

let the rate charged by first mechanic be x .

let the rate charged by second mechanic be y.

According to question

x +y=95-----------1

20x+15y=1650----------2

Multiply equation 1 by 20 and subtract equation 2 from 1.

20x+20y-20x-15y=1900-1650

5y=250

y=50

put the value of y=50 in 1 to get the value of x.

x +y=95

x+50=95

x=95-50

x=45

Hence the rate charged by first mechanic is $45 per hour and the rate charged by second mechanic is $50 per hour.

Learn more about equation at brainly.com/question/2972832

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Question is incomplete as it should be as under:

Two mechanics worked on a car, the first mechanic worked 20 hrs. and the second mechanic worked 15 hours together. They charged a total of $ 1650. What is the rate charged per hour for each mechanic if the sum of the two rates per hour was $95 per hour?

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Given the polynomial function f(x) = log(1+x) …...(1) centered at x=0

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using formula $\frac{d}{dx} x^{n-1} =nx^{n-1}$

Again Differentiating Equation(2) with respective to 'x' we get

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and so on...

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Step :-2

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At x=a =0

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Substitute all values , we get

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On simplification we get

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