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Gelneren [198K]
3 years ago
9

If a figure located at T(-3, -1), U(1, -2), V(2, 2), W(-1, 1) and is rotated 90∘ counterclockwise rotation about the origin, whi

ch point would be the correct location of T'?
(a) (2, 1)

(b) (-1, -1)

(c) (1, -3)

(d) (-2, 2)
Mathematics
1 answer:
damaskus [11]3 years ago
3 0

Answer:

(1, - 3 )

Step-by-step explanation:

Under a counterclockwise rotation about the origin of 90°

a point (x, y ) → (- y, x ), thus

T(- 3, - 1 ) → T'(1, - 3 )

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The mean monthly car payment for 123 residents of the local apartment complex is $624. What is the best point estimate for the m
Natali [406]

Answer:

The best point estimate for the mean monthly car payment for all residents of the local apartment complex is $624.

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

In this question:

We apply the inverse Central Limit Theorem.

The mean monthy car payment for 123 residents of the local apartment complex is $624.

So, for all residents of the local apartment complex, the best point estimate for the mean monthly car payment is $624.

3 0
3 years ago
What is the domain for f(x) =26-2x?
anastassius [24]
Domain of f = R .............
7 0
3 years ago
One number is five more than a second number. The product of the numbers is 3,300. Find the two numbers
krek1111 [17]
A = b+5
ab = 3300
(b+5)b = 3300
b² +5b -3300 = 0  (quadratic formula)
b=55
a=60      (by first relation)
7 0
4 years ago
O is the centre of the circle, EF is a tangent, angle BCE = 28°, angle ACD = 31°
andriy [413]

Answer

a. 28˚

b. 76˚

c. 104˚

d. 56˚

Step-by-step explanation

Given,

∠BCE=28°  ∠ACD=31°  &  line AB=AC .

According To the Question,

  • a. the angle between a chord and a tangent through one of the end points of the chord is equal to the angle in the alternate segment.(Alternate Segment Theorem) Thus, ∠BAC=28°

  • b. We Know The Sum Of All Angles in a triangle is 180˚, 180°-∠CAB(28°)=152° and ΔABC is an isosceles triangle, So 152°/2=76˚

        thus , ∠ABC=76° .

  • c. We know the Sum of all angles in a triangle is 180° and opposite angles in a cyclic quadrilateral(ABCD) add up to 180˚,

Thus, ∠ACD + ∠ACB = 31° + 76° ⇔ 107°

Now, ∠DCB + ∠DAB = 180°(Cyclic Quadrilateral opposite angle)

∠DAB = 180° - 107° ⇔ 73°

& We Know, ∠DAC+∠CAB=∠DAB ⇔ ∠DAC = 73° - 28° ⇔ 45°

Now, In Triangle ADC Sum of angles in a triangle is 180°

∠ADC = 180° - (31° + 45°)  ⇔  104˚

   

  • d. ∠COB = 28°×2 ⇔ 56˚ , because With the Same Arc(CB) The Angle at circumference are half of the angle at the centre  

For Diagram, Please Find in Attachment  

4 0
3 years ago
To avoid a storm a passenger jet pilot decendents 0.44 mile in 0.8 minute.what was the planes average change in altitude per min
Lemur [1.5K]
.44/.8=×/1
×=.55
..................................
8 0
3 years ago
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