Find the maximum and minimum values of the function g(θ) 5θ-9sin(θ) on the interval [0, π] Minimum value =

Are all sides of the right angle have sides that are parallel

nydimaria [60]

-- The two sides of a right <u>angle</u> intersect and make the angle.
So do the sides of any other angle. So they can't be parallel.

-- No two sides of a right <u>triangle</u> ... or any other triangle ...can be parallel.

8 0

4 years ago

find the present and future value of $1000 received every month end for 20 years if the interest rate is j12=12%p.a

GenaCL600 [577]

Answer:

asasassasas

Step-by-step explanation:

4 0

3 years ago

What is the completely factored form of f(x)=x3+5x2+4x−6?

Gre4nikov [31]

$f(x)=x^3+5x^2+4x-6$
$f(-3)=(-3)^3+5(-3)^2+4(-3)-6=0\implies x+3\text{ is a factor of }f(x)$

Synthetic division yields

-3 | 1   5   4   -6
.    |      -3 -6    6
- - - - - - - - - - - - -
.    | 1   2 -2    0

which translates to

$\dfrac{x^3+5x^2+4x-6}{x+3}=x^2+2x-2$

with remainder 0. Now by the quadratic formula,

$x^2+2x-2=0\implies x=\dfrac{-2\pm\sqrt{2^2-4(1)(-2)}}2=-1\pm\sqrt3$

and so

$f(x)=x^3+5x^2+4x-6=(x+3)(x-(-1+\sqrt3))(x-(-1-\sqrt3))$

3 0

3 years ago

"All parallelograms have two pairs of parallel sides. All rectangles are parallelograms with four right angles. All squares are

Lorico [155]

A. Yes, since a square is a type of rectangle, but it has four congruent and parallel side.
B. Yes, since a square is also a type of parallelogram. Therefore it has 2 pairs of parallel sides.
C. No, they have 2 pairs of congruent sides.
Hope this helps :D

4 0

4 years ago

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Arrange the circles (represented by their equations in general form) in ascending order of their radius lengths. X2 y2 − 2x 2y −

Colt1911 [192]

Circles (represented by their equations in general form) in ascending order of their radius lengths can be arranged as first-fifth-second-forth-third-seventh-sixth.

<h3>What is the equation of circle?</h3>

The equation of the circle is the equation which is used to represent the circle in the algebraic equation form with the value of center point in the coordinate plane and measure of radius.

The standard form of the equation of the circle can be given as,

$(x-h)^2+(y-k)^2=r^2$

Here (h,k) is the center of the circle and (r) is the radius of the circle.

Lets arrange the first equation, in standard form of equation of circle as,

$x^2 +y^2 - 2x+ 2y -1 = 0 \\(x^2 - 2x) +(y^2+ 2y )= 1\\(x^2 - 2x+1) +(y^2+ 2y +1)= 1+1+1\\(x-1)^2+(y+1)^2=(\sqrt{3})^2$

The radius of this circle is √(3).

Lets arrange the second equation, in standard form of equation of circle as,

$x^2 +y^2 - 4x+ 4y - 10 = 0 \\(x^2 - 4x) +(y^2+ 4y )= 10\\(x^2 - 4x+4) +(y^2+ 4y +4)= 10+4+4\\(x-2)^2+(y+2)^2=(\sqrt{18})^2$

The radius of this circle is √(18).

Lets arrange the third equation, in standard form of equation of circle as,

$x^2 +y^2 - 8x - 6y - 20 = 0 \\(x^2 - 8x) +(y^2-6y )= 20\\(x^2 - 8x+16) +(y^2- 6y +9)= 10+16+9\\(x-4)^2+(y-3)^2=(\sqrt{45})^2$

The radius of this circle is √(45).

Similarly, radius of the forth, fifth, sixth and seventh circle is √(23), √(5), √(117) and √(46) units.

Hence, the circles (represented by their equations in general form) in ascending order of their radius lengths can be arranged as first-fifth-second-forth-third-seventh-sixth.

Learn more about the equation of circle here;

brainly.com/question/1506955

3 0

2 years ago

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