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3 years ago

Write a quadratic function f whose zeros are 6 and -5 .

Mathematics

2 answers:

Iteru [2.4K]3 years ago

7 0

Answer: f(x) = x² - x - 30

Step-by-step explanation:

Here's a really simple way.

Quadratic equations are the product of two first order equations such as

f(x) = (x + A)(x + B)

intercepts mean the function result is zero, which means that either

(x + A) = 0 or (x + B) = 0

if x + A = 0 then x = - A

if x + B = 0 then x = -B

So all we have to do is to negate the numbers and add x to make the factor

Long story short, this example looks like this

(x - 6)(x + 5) = x² - x - 30

dexar [7]3 years ago

4 0

Answer:

so ez

Step-by-step explanation:

HI IM INDIAN AND STUDING IN 10TH GRADE U?

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Suppose a certain state university's college of business obtained the following results on the salaries of a recent graduating c

Lerok [7]

Answer:

Following are the responses to the given choice:

Step-by-step explanation:

For point a:

$H_0: \mu_1 - \mu_2 = 0\\\\ H_1: \mu_1 - \mu_2 < 0$

For point b:

$t = -2.953$

For point c:

$\to p- value = 0.0021$

For point d:

Reject $H_o$ . It could deduce that the pay of higher banking is considerably lower than the pay of higher project management.

7 0

3 years ago

You need to fence in a rectangular piece of land for your dog to run and play. The length is 3 times the width. If the perimeter

nikitadnepr [17]

Answer:

Width = 15 feet

Length = 45 feet

Step-by-step explanation:

You need to fence in a rectangular piece of land for your dog to run and play. The length is 3 times the width. If the perimeter is 120 ft, what are the dimensions of your very own dog park?

Perimeter of a rectangle = 2L + 2W

The length is 3 times the width.

L = Length = 3W

W = Width

P = 120 ft

Hence:

120 = 2L + 2W

120 = 2(3W) + 2W

120 = 6W + 2W

120 = 8W

W = 120/8

W = 15 feet

Solving for Length

L = 3W

L = 3 × 15 feet

L = 45 feet

Therefore, the dimensions of your very own dog park is

Width = 15 feet

Length = 45 feet

3 0

3 years ago

6-11x=7x-12 how do you solve

tekilochka [14]

Use Cymath it helps and give u the answer

6 0

3 years ago

A school choir has 80 students; 36 of them are in seventh grade. Also, 40 students in the choir are girls; 18 of them are in sev

Sati [7]

B. 29/40

40-18=22
22+36=58/80
58/2=29
80/2=40

7 0

3 years ago

Read 2 more answers

Use spherical coordinates. Find the volume of the solid that lies within the sphere x^2 + y^2 + z^2 = 81, above the xy-plane, an

Natasha_Volkova [10]

Answer:

The volume of the solid is 243 $\sqrt{2} \ \pi$

Step-by-step explanation:

From the information given:

BY applying sphere coordinates:

0 ≤ x² + y² + z² ≤ 81

0 ≤ ρ² ≤ 81

0 ≤ ρ ≤ 9

The intersection that takes place in the sphere and the cone is:

$x^2 +y^2 ( \sqrt{x^2 +y^2 })^2 = 81$

$2(x^2 + y^2) =81$

$x^2 +y^2 = \dfrac{81}{2}$

Thus; the region bounded is: 0 ≤ θ ≤ 2π

This implies that:

$z = \sqrt{x^2+y^2}$

ρcosФ = ρsinФ

tanФ = 1

Ф = π/4

Similarly; in the X-Y plane;

z = 0

ρcosФ = 0

cosФ = 0

Ф = π/2

So here; $\dfrac{\pi}{4} \leq \phi \le \dfrac{\pi}{2}$

Thus, volume: $V = \iiint_E \ d V = \int \limits^{\pi/2}_{\pi/4} \int \limits ^{2\pi}_{0} \int \limits^9_0 \rho ^2 \ sin \phi \ d\rho \ d \theta \ d \phi$

$V = \int \limits^{\pi/2}_{\pi/4} \ sin \phi \ d \phi \int \limits ^{2\pi}_{0} d \theta \int \limits^9_0 \rho ^2 d\rho$

$V = \bigg [-cos \phi \bigg]^{\pi/2}_{\pi/4} \bigg [\theta \bigg]^{2 \pi}_{0} \bigg [\dfrac{\rho^3}{3} \bigg ]^{9}_{0}$

$V = [ -0+ \dfrac{1}{\sqrt{2}}][2 \pi -0] [\dfrac{9^3}{3}- 0 ]$

V = 243 $\sqrt{2} \ \pi$

4 0

3 years ago