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3 years ago

Write a quadratic function f whose zeros are 6 and -5 .

Mathematics

2 answers:

Iteru [2.4K]3 years ago

7 0

Answer: f(x) = x² - x - 30

Step-by-step explanation:

Here's a really simple way.

Quadratic equations are the product of two first order equations such as

f(x) = (x + A)(x + B)

intercepts mean the function result is zero, which means that either

(x + A) = 0 or (x + B) = 0

if x + A = 0 then x = - A

if x + B = 0 then x = -B

So all we have to do is to negate the numbers and add x to make the factor

Long story short, this example looks like this

(x - 6)(x + 5) = x² - x - 30

dexar [7]3 years ago

4 0

Answer:

so ez

Step-by-step explanation:

HI IM INDIAN AND STUDING IN 10TH GRADE U?

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mr.browns salary is 32,000 and imcreases by $300 each year, write a sequence showing the salary for the first five years when wi

chubhunter [2.5K]

Hello!

We have the following data:

a1 (first term or first year salary) = 32000

r (ratio or annual increase) = 300

n (number of terms or each year worked)

We apply the data in the Formula of the General Term of an Arithmetic Progression, to find in sequence the salary increases until it exceeds 34700, let us see:

formula:

$a_n = a_1 + (n-1)*r$

* second year salary

$a_2 = a_1 + (2-1)*300$

$a_2 = 32000 + 1*300$

$a_2 = 32000 + 300$

$\boxed{a_2 = 32300}$

* third year salary

$a_3 = a_1 + (3-1)*300$

$a_3 = 32000 + 2*300$

$a_3 = 32000 + 600$

$\boxed{a_3 = 32600}$

* fourth year salary

$a_4 = a_1 + (4-1)*300$

$a_4 = 32000 + 3*300$

$a_4 = 32000 + 900$

$\boxed{a_4 = 32900}$

* fifth year salary

$a_5 = a_1 + (5-1)*300$

$a_5 = 32000 + 4*300$

$a_5 = 32000 + 1200$

$\boxed{a_5 = 33200}$

We note that after the first five years, Mr. Browns' salary has not yet surpassed 34700, let's see when he will exceed the value:

* sixth year salary

$a_6 = a_1 + (6-1)*300$

$a_6 = 32000 + 5*300$

$a_6 = 32000 + 1500$

$\boxed{a_6 = 33500}$

* seventh year salary

$a_7 = a_1 + (7-1)*300$

$a_7 = 32000 + 6*300$

$a_7 = 32000 + 1800$

$\boxed{a_7 = 33800}$

* eighth year salary

$a_8 = a_1 + (8-1)*300$

$a_8 = 32000 + 7*300$

$a_8 = 32000 + 2100$

$\boxed{a_8 = 34100}$

* ninth year salary

$a_9 = a_1 + (9-1)*300$

$a_9 = 32000 + 8*300$

$a_9 = 32000 + 2400$

$\boxed{a_9 = 34400}$

* tenth year salary

$a_{10} = a_1 + (10-1)*300$

$a_{10} = 32000 + 9*300$

$a_{10} = 32000 + 2700$

$\boxed{a_{10} = 34700}$

we note that in the tenth year of salary the value equals but has not yet exceeded the stipulated value, only in the eleventh year will such value be surpassed, let us see:

* eleventh year salary

$a_{11} = a_1 + (11-1)*300$

$a_{11} = 32000 + 10*300$

$a_{11} = 32000 + 3000$

$\boxed{\boxed{a_{11} = 35000}}\end{array}}\qquad\checkmark$

Respuesta:

In the eleventh year of salary he will earn more than 34700, in the case, this value will be 35000

________________________

¡Espero haberte ayudado, saludos... DexteR! =)

7 0

3 years ago

Kara is 18 years younger than Joseph. Twelve years ago, Joseph was 4 times as old as Kara. Find their present ages.

prohojiy [21]

To solve this, first you need to jump back the clock. so 18 minus 12 is 6. scince at that time joseph was 4 times older, 6 times 4 is 24. add that to 12 and you get 36. but we need to check our work. if 36 minus 18 isint 18 then we screwed up. but, we didnt. so now, Kara is 18 years old and Joseph is 36 years old.

8 0

4 years ago

Read 2 more answers

Describe in your own words the characteristics of linear equations that determine whether a system of linear equations will be I

Hunter-Best [27]

Step-by-step explanation:

i) An intersecting system of linear equations

A system of linear equations comprises of two or more linear equations. Linear equations are simply straight line equations with a given slope and a unique y-intercept .

Solutions to systems of linear equations can be determined using a number of techniques among them being;

Elimination method

Substitution method

Graphical method

The graphs of a system of linear equations will intersect at a unique single point if the lines are not parallel.

An example of intersecting system of linear equations;

y = 2x -5 and y =5x + 4

The two lines will intersect at a particular single point since the slopes are not identical. The attachment below demonstrates this aspect.

ii) A parallel system of linear equations

Two lines are said to be parallel if they have an identical slope but unique y-intercepts. Parallel lines never intersect at any given point since the perpendicular distance between them is always constant.

Thus a parallel system of linear equations has no solution. An example of parallel system of linear equations;

y = 3x - 4 and y = 3x + 8

The attachment below demonstrates this aspect.

iii) A coincident system of linear equations

A system of linear equations is said to be coincident if the two straight lines are identical. That is the lines have an identical slope and y-intercept. Basically, we are just looking at the same line. Two parallel lines can also intersect if they are coincident, which means they are the same line and they intersect at every point.

Therefore, this system of linear equations will have an infinite number of solutions.

4 0

3 years ago

Need help ASAP !!!<br><br><img src="https://tex.z-dn.net/?f=%20%5Csqrt%7B012%20%5Ctimes%2012%7D%20" id="TexFormula1" title=" \sq

lutik1710 [3]

Answer:

your answer will be 12

Step-by-step explanation:

thanks for the points man!!!

8 0

3 years ago

1. In 2005, there were 100 rabbits in Polygon Park. The population increased by

Olegator [25]

The exponential growth formula is y = a(1+r)^x

y = 100(1+.11)^t

6 0

4 years ago