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yuradex [85]
2 years ago
9

A delivery of 5 large boxes and 3 small boxes has a total mass of 137 kilograms. A delivery of 2 large boxes and 6 small boxes h

as a total mass of 128 kilograms. What is the mass of each type of box?
Mathematics
1 answer:
lawyer [7]2 years ago
7 0

Answer:

Large boxes are 18.25 kg

Small boxes are 15.25 kg

Step-by-step explanation:

This is a system of equations. You need to set up each equation first.

I am assigning x to be big boxes and y to be small boxes.

5x + 3y = 137

2x + 6y = 128

To solve, you will need to eliminate a variable. That means you will have to multiply one of the equations by a number to make it so a variable will be eliminated. I will be multiplying the top equation by -2.

-2 ( 5x + 3y = 137)

    2x + 6y = 128

Distribute the -2 to everything in the parentheses in the first equation.

-10x - 6y = -274

2x + 6y = 128

Notice the 6y will go away because -6y + 6y = 0. Now add the equations together. The remaining equation is:

-8x = -146

Solve for x by dividing by -8.

x = 18.25

Now plug that into one of the original equations.

2(18.25) + 6y = 128.

36.5 + 6y = 128                Subtract 36.5 from each side

-36.5            -36.5

6y = 91.5                          Divide by 6 to solve

y = 15.25

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3 years ago
A 10-foot ladder is leaning against a wall. The base of the ladder is 2 feet from the base of the building. How far up the build
Svetlanka [38]
We can see on this graph that the triangle has legs of x and 6 with a hypotenuse of 10 and we can use Pythagoreans theorem to find the unknown side.
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x^2+6^2=10^2 Plugin a=x, b=6, and c=10. Now let us solve for x 

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5 0
3 years ago
Composition of functions Find g (f(x)) for the following problems
beks73 [17]

1.

f(x)=-3x\qquad g(x)=5x-6\\\\g(f(x))=5(-3x)-6=\boxed{-15x-6}

2.

f(x)=x-6\qquad g(x)=x^2+6x-2\\\\g(f(x))=(x-6)^2+6(x-6)-2=x^2-12x+36+6x-36-2=\\\\=\boxed{x^2-6x-2}

3.

f(x)=4x+3\qquad g(x)=2x^2-x+1\\\\g(f(x))=2(4x+3)^2-(4x+3)+1=2(16x^2+24x+9)-4x-3+1=\\\\=32x^2+48x+18-4x-3+1=\boxed{32x^2+44x+16}

4.

f(x)=2x^2\qquad g(x)=8x^2+3x\\\\g(f(x))=8(2x^2)^2+3(2x^2)=8\cdot4x^4+6x^2=\boxed{32x^4+6x^2}

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3 years ago
Costs related to rent, utilities, administration, equipment use and/or depreciation are called overhead.
deff fn [24]
true
Typically, the price charged must cover more than labor costs figured at an hourly rate. There may be costs related to rent, utilities, administration, equipment use and/or depreciation. These costs are often called overhead<span>.</span>
6 0
3 years ago
Read 2 more answers
The perimeter of a rectangular field is 168 feet. The field is 36 feet wide. How long is the field
Dmitriy789 [7]
To find the length, divide the peremiter by 2 and then subtract the width.

Length= Peremiter/2 - width
L = P/2 - W
L = 168/2 - 36
L = 84 - 36
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The length is 48
7 0
4 years ago
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