A delivery of 5 large boxes and 3 small boxes has a total mass of 137 kilograms. A delivery of 2 large boxes and 6 small boxes h
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16% percent of the students paid MORE than Jane.
The mean(μ) of money spent on textbooks is 500
The standard deviation(σ) of money spent on textbooks is 50
Money paid by Jane for her books is $550
We will use this formula,
Ζ=x-μ/σ
To find: the percentage of students paid MORE than Jane for the textbooks
=?
Solution:
≤
=Ζ≤
=1-P(Ζ≤ 1)
=1-0.8413
=0.1587
≈16%
Therefore, 16% percent (approx) of the students paid MORE than Jane.
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30 pounds of raspberries and 50 pounds of blueberries are sold
<em><u>Solution:</u></em>
Let "a" be the pounds of raspberries sold
Let "b" be the pounds of blueberries sold
Cost per pound of raspberry = $ 1
Cost per pound of blue berry = $ 3.25
<em><u>Maya made $192.50 from selling a total of 80 pounds of raspberries and blueberries</u></em>
Therefore,
a + b = 80
a = 80 - b ------- eqn 1
<em><u>Maya made $192.50. Therefore, frame a equation as:</u></em>
pounds of raspberries sold x Cost per pound of raspberry + pounds of blueberries sold x Cost per pound of blue berry = 192.50
a + 3.25b = 192.50 ------ eqn 2
<em><u>Let us solve eqn 1 and eqn 2</u></em>
<em><u>Substitute eqn 1 in eqn 2</u></em>
80 - b + 3.25b = 192.50
2.25b = 192.50 - 80
2.25b = 112.5
Divide both sides by 2.25
b = 50
<em><u>Substitute b = 50 in eqn 1</u></em>
a = 80 - 50
a = 30
Thus 30 pounds of raspberries and 50 pounds of blueberries are sold