Answer:
2: no
3: no
4: no
5: yes
6: no
8: no
9: no
10: no
11: yes
Step-by-step explanation:
there are some simple divisibility rules that we can utilize here:
a number is divisible by __ if...
2: ends in [last digit] 0, 2, 4, 6, 8
<em>so 27</em><em>5 </em><em>is </em><em>not </em><em>divisible by 2</em>
3: sum of digits is 3
2 + 7 + 5 = 14 [14 is not divisible by 3]
<em>so 275 is </em><em>not </em><em>divisible by 3</em>
4: last two digits are divisible by 4
75 is not divisible by 4
<em>so 275 is </em><em>not </em><em>divisible by 4</em>
5: last digit is 0 or 5
<em>so 27</em><em>5 is </em><em>divisible by 5</em>
6: number is divisible by both 2 and 3
<em>we know that 175 is not divisible by 2 or 3, so 275 is </em><em>not </em><em>divisble by 6</em>
8: last three digits are divisible by 8
>> we also know that any number that 8 goes into, 4 also goes into [not always the other way around], meaning that because 175 is not divisible by 4, it must not be divisible by 8
<em>so, 275 is </em><em>not </em><em>divisible by 8</em>
9: sum of digits is divisible by 9
>> we also know that 9 only can go into numbers that 3 can go into, so because 175 is not divisible by 3, it must not be divisible by 9
<em>so, 275 is not divisible by 9</em>
10: last digit is 0
<em>so, 27</em><em>5</em><em> is </em><em>not </em><em>divisible by 10</em>
11 is a bit complicated:
sum of digit in odd places and sum of digit in even places has a difference is divisible by 11 [or is 0]
2 7 5
odd places: 2, 5 (2 + 5 = 7)
even places: 7 (7 = 7)
difference between 7 and 7 is 0 (7-7 = 0),
so, <em>275 </em><em>is</em><em> divisible by 11</em>
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hope this helps!! :)