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Mice21 [21]
4 years ago
11

An _______ is a value that is far removed from the rest of the values in a set of data.

Mathematics
2 answers:
ale4655 [162]4 years ago
7 0

Answer:

The answer is an outlier. An outlier is any number within a data set that is either significantly higher or significantly lower than the majority of the numbers.

Veronika [31]4 years ago
3 0

Answer:

answer is outliner

Step-by-step explanation:

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Express 9 - y2 as the product of two binomial factors
Gwar [14]
Binomial factors are where two factors are being added. For a²-b², it can be written as (a-b)*(a+b). Writing it out, we know that 9=3², so we can make it
 (3-y)(3+y)
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4 years ago
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The daily cost of renting a car is $25.00 plus $0.30 per mile driven. What is the cost of renting the car for one day and drivin
alekssr [168]

Answer: The cost of renting the car for one day and driving at 75 miles = $ 47.5 .

Step-by-step explanation:

GIven: Daily cost of renting car = $ 25.00 + $0.30 per mile driven

Let x = Total distance traveled ( in miles).

Then total cost of renting (in $)= 25+0.30x

For x= 75 miles

The  total cost of renting (in $)= 25+0.30(75)

=25+22.5

= $47.5

Hence, the cost of renting the car for one day and driving at 75 miles = $ 47.5

4 0
3 years ago
Find the length of a leg
N76 [4]
The answer to your question is b.
8 0
4 years ago
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The points in the table lie on a line. Find the slope of the line
8090 [49]

Answer:

1/2

Step-by-step explanation:

Pick two of the x's and y's

The first two columns in the table, the x's are -2 and 0 and the y's are 3 and 4.

The x value changes as a +2 and the y value changes from a +1 from the first two columns. Put the +2 as the denominator and the +1 as the numerator. 1/2

5 0
3 years ago
Solve the equation using the substitution u = y/x. When u = y/x is substituted into the equation, the equation becomes separable
bekas [8.4K]

Answer:

\frac{u^2+3}{-u^3+u^2-2u}u'=\frac{1}{x}

Step-by-step explanation:

First step: I'm going to solve our substitution for y:

u=\frac{y}{x}

Multiply both sides by x:

ux=y

Second step: Differentiate the substitution:

u'x+u=y'

Third step: Plug in first and second step into the given equation dy/dx=f(x,y):

u'x+u=\frac{x(ux)+(ux)^2}{3x^2+(ux)^2}

u'x+u=\frac{ux^2+u^2x^2}{3x^2+u^2x^2}

We are going to simplify what we can.

Every term in the fraction on the right hand side of equation contains a factor of x^2 so I'm going to divide top and bottom by x^2:

u'x+u=\frac{u+u^2}{3+u^2}

Now I have no idea what your left hand side is suppose to look like but I'm going to keep going here:

Subtract u on both sides:

u'x=\frac{u+u^2}{3+u^2}-u

Find a common denominator: Multiply second term on right hand side by \frac{3+u^2}{3+u^2}:

u'x=\frac{u+u^2}{3+u^2}-\frac{u(3+u^2)}{3+u^2}

Combine fractions while also distributing u to terms in ( ):

u'x=\frac{u+u^2-3u-u^3}{3+u^2}

u'x=\frac{-u^3+u^2-2u}{3+u^2}

Third step: I'm going to separate the variables:

Multiply both sides by the reciprocal of the right hand side fraction.

u' \frac{3+u^2}{-u^3+u^2-2u}x=1

Divide both sides by x:

\frac{3+u^2}{-u^3+u^2-2u}u'=\frac{1}{x}

Reorder the top a little of left hand side using the commutative property for addition:

\frac{u^2+3}{-u^3+u^2-2u}u'=\frac{1}{x}

The expression on left hand side almost matches your expression but not quite so something seems a little off.

5 0
3 years ago
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